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hoa [83]
2 years ago
12

Use the figure for 10 - 12. X is the midpoint of PQ.10: Find PX 11. Find XQ 12. Find PQ​

Mathematics
2 answers:
makkiz [27]2 years ago
8 0

Answer:

see explanation

Step-by-step explanation:

since X is the midpoint of PQ , then

PX = QX ( substitute values )

4x + 15 = 7x + 6 ( subtract 4x from both sides )

15 = 3x + 6 ( subtract 6 from both sides )

9 = 3x ( divide both sides by 3 )

3 = x

Then

PX = 4x + 15 = 4(3) + 15 = 12 + 15 = 27

XQ = 7x + 6 = 7(3) + 6 = 21 + 6 = 27

PQ = PX + XQ = 27 + 27 = 54

qaws [65]2 years ago
4 0

Answer:

PX = 4x + 15 = 4(3) + 15 = 12 + 15 = 27

XQ = 7x + 6 = 7(3) + 6 = 21 + 6 = 27

PQ = PX + XQ = 27 + 27 = 54

Step-by-step explanation:

Since X is the midpoint of PQ , then

PX = QX ( substitute values )

4x + 15 = 7x + 6 ( subtract 4x from both sides )

15 = 3x + 6 ( subtract 6 from both sides )

9 = 3x ( divide both sides by 3 )

3 = x

Then

PX = 4x + 15 = 4(3) + 15 = 12 + 15 = 27

XQ = 7x + 6 = 7(3) + 6 = 21 + 6 = 27

PQ = PX + XQ = 27 + 27 = 54

Hence, the correct answers are: PX = 4x + 15 = 4(3) + 15 = 12 + 15 = 27

XQ = 7x + 6 = 7(3) + 6 = 21 + 6 = 27 PQ = PX + XQ = 27 + 27 = 54

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Answer:

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Step-by-step explanation:

Given:

\sqrt[3]{256x^{10}y^{7} }

Solution:

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