Who would go in the answer section and say that they type to get points
Answer:
B
Step-by-step explanation:
Took it
Answer:
A math test
Step-by-step explanation:
I just Goggled it lol
Answer: 0.1310
Step-by-step explanation:
Given : Mean : ![\mu = \text{131 millimeters}](https://tex.z-dn.net/?f=%5Cmu%20%3D%20%5Ctext%7B131%20millimeters%7D)
Standard deviation : ![\sigma = \text{7 millimeters}](https://tex.z-dn.net/?f=%5Csigma%20%3D%20%5Ctext%7B7%20millimeters%7D)
Sample size : ![n=31](https://tex.z-dn.net/?f=n%3D31)
To find the probability that the sample mean would differ from the population mean by more than 1.9 millimeters i.e. less than 129.1 milliliters and less than 132.9 milliliters.
The formula for z-score :-
![z=\dfrac{x-\mu}{\dfrac{\sigma}{\sqrt{n}}}](https://tex.z-dn.net/?f=z%3D%5Cdfrac%7Bx-%5Cmu%7D%7B%5Cdfrac%7B%5Csigma%7D%7B%5Csqrt%7Bn%7D%7D%7D)
For x = 129.1 milliliters
![z=\dfrac{129.1-131}{\dfrac{7}{\sqrt{31}}}\approx-1.51](https://tex.z-dn.net/?f=z%3D%5Cdfrac%7B129.1-131%7D%7B%5Cdfrac%7B7%7D%7B%5Csqrt%7B31%7D%7D%7D%5Capprox-1.51)
For x = 132.9 milliliters
![z=\dfrac{132.9-131}{\dfrac{7}{\sqrt{31}}}\approx1.51](https://tex.z-dn.net/?f=z%3D%5Cdfrac%7B132.9-131%7D%7B%5Cdfrac%7B7%7D%7B%5Csqrt%7B31%7D%7D%7D%5Capprox1.51)
The P-value= ![P(x1.51)](https://tex.z-dn.net/?f=P%28x%3C-1.51%29%2BP%28x%3E1.51%29)
![=2P(z>1.51)=2(1-P(z](https://tex.z-dn.net/?f=%3D2P%28z%3E1.51%29%3D2%281-P%28z%3C1.15%29%29%5C%5C%3D2%281-0.9344783%29%5C%5C%3D0.1310434%5Capprox0.1310)
Hence, the required probability = 0.1310
Answer:
![1\ \frac{\text{cal}}{m^2\times sec\times ^\circ C}=0.03926\frac{\text{BTU}}{ft^2\times hr\times ^\circ F}](https://tex.z-dn.net/?f=1%5C%20%5Cfrac%7B%5Ctext%7Bcal%7D%7D%7Bm%5E2%5Ctimes%20sec%5Ctimes%20%5E%5Ccirc%20C%7D%3D0.03926%5Cfrac%7B%5Ctext%7BBTU%7D%7D%7Bft%5E2%5Ctimes%20hr%5Ctimes%20%5E%5Ccirc%20F%7D)
Step-by-step explanation:
To find : Convert
into ![\frac{\text{BTU}}{ft^2\times hr\times ^\circ F}](https://tex.z-dn.net/?f=%5Cfrac%7B%5Ctext%7BBTU%7D%7D%7Bft%5E2%5Ctimes%20hr%5Ctimes%20%5E%5Ccirc%20F%7D)
Solution :
We convert units one by one,
![1\text{ m}^2=10.7639\text{ ft}^2](https://tex.z-dn.net/?f=1%5Ctext%7B%20m%7D%5E2%3D10.7639%5Ctext%7B%20ft%7D%5E2)
![1\text{ sec}=\frac{1}{3600}\text{ hour}](https://tex.z-dn.net/?f=1%5Ctext%7B%20sec%7D%3D%5Cfrac%7B1%7D%7B3600%7D%5Ctext%7B%20hour%7D)
![1\text{ cal}=0.003968\text{ BTU}](https://tex.z-dn.net/?f=1%5Ctext%7B%20cal%7D%3D0.003968%5Ctext%7B%20BTU%7D)
Converting temperature unit,
![^\circ C\times \frac{9}{5}+32=^\circ F](https://tex.z-dn.net/?f=%5E%5Ccirc%20C%5Ctimes%20%5Cfrac%7B9%7D%7B5%7D%2B32%3D%5E%5Ccirc%20F)
![1^\circ C\times \frac{9}{5}+32=33.8^\circ F](https://tex.z-dn.net/?f=1%5E%5Ccirc%20C%5Ctimes%20%5Cfrac%7B9%7D%7B5%7D%2B32%3D33.8%5E%5Ccirc%20F)
So, ![1^\circ C=33.8^\circ F](https://tex.z-dn.net/?f=1%5E%5Ccirc%20C%3D33.8%5E%5Ccirc%20F)
Substitute all the values in the unit conversion,
![1\ \frac{\text{cal}}{m^2\times sec\times ^\circ C}=\frac{0.003968}{10.7639\times \frac{1}{3600}\times 33.8}\frac{\text{BTU}}{ft^2\times hr\times ^\circ F}](https://tex.z-dn.net/?f=1%5C%20%5Cfrac%7B%5Ctext%7Bcal%7D%7D%7Bm%5E2%5Ctimes%20sec%5Ctimes%20%5E%5Ccirc%20C%7D%3D%5Cfrac%7B0.003968%7D%7B10.7639%5Ctimes%20%5Cfrac%7B1%7D%7B3600%7D%5Ctimes%2033.8%7D%5Cfrac%7B%5Ctext%7BBTU%7D%7D%7Bft%5E2%5Ctimes%20hr%5Ctimes%20%5E%5Ccirc%20F%7D)
![1\ \frac{\text{cal}}{m^2\times sec\times ^\circ C}=\frac{0.003968}{0.101061}\frac{\text{BTU}}{ft^2\times hr\times ^\circ F}](https://tex.z-dn.net/?f=1%5C%20%5Cfrac%7B%5Ctext%7Bcal%7D%7D%7Bm%5E2%5Ctimes%20sec%5Ctimes%20%5E%5Ccirc%20C%7D%3D%5Cfrac%7B0.003968%7D%7B0.101061%7D%5Cfrac%7B%5Ctext%7BBTU%7D%7D%7Bft%5E2%5Ctimes%20hr%5Ctimes%20%5E%5Ccirc%20F%7D)
![1\ \frac{\text{cal}}{m^2\times sec\times ^\circ C}=0.03926\frac{\text{BTU}}{ft^2\times hr\times ^\circ F}](https://tex.z-dn.net/?f=1%5C%20%5Cfrac%7B%5Ctext%7Bcal%7D%7D%7Bm%5E2%5Ctimes%20sec%5Ctimes%20%5E%5Ccirc%20C%7D%3D0.03926%5Cfrac%7B%5Ctext%7BBTU%7D%7D%7Bft%5E2%5Ctimes%20hr%5Ctimes%20%5E%5Ccirc%20F%7D)
Therefore, The conversion of unit is ![1\ \frac{\text{cal}}{m^2\times sec\times ^\circ C}=0.03926\frac{\text{BTU}}{ft^2\times hr\times ^\circ F}](https://tex.z-dn.net/?f=1%5C%20%5Cfrac%7B%5Ctext%7Bcal%7D%7D%7Bm%5E2%5Ctimes%20sec%5Ctimes%20%5E%5Ccirc%20C%7D%3D0.03926%5Cfrac%7B%5Ctext%7BBTU%7D%7D%7Bft%5E2%5Ctimes%20hr%5Ctimes%20%5E%5Ccirc%20F%7D)