a(1) = 3(1)-1 = 3-1 = 2
a(2) = 3(2)-1 = 6-1 = 5
a(3) = 3(3)-1 = 9-1 = 8
So, the sequence would be 2,5,8,11....
<span>r^2 = 529 - 46x + x^2 + 64
r^2 = x^2 - 46x + 593
replace r^2 with (x^2+ 225)
x^2 + 225 = x^2 - 46x + 593
x^2 - x^2 + 46x = 593 - 225
46x = 368
x = 368/46
x = 8 cm
Find the radius
r^2 = 8^2 + 225
r^2 = 289
r =
r = 17 cm is the radius</span>
3 is the gcf of 21 and 30
First let's model the carpet as a rectangle.
The diagonal of a rectangle is given by:
d = root ((L) ^ 2 + (W) ^ 2)
Where,
L = long
W = width.
Clearing the width we have:
d = root ((L) ^ 2 + (W) ^ 2)
d ^ 2 = (L) ^ 2 + (W) ^ 2
(W) ^ 2 = (d) ^ 2- (L) ^ 2
W = root ((d) ^ 2- (L) ^ 2)
Substituting the values
W = root ((root (89)) ^ 2- (8) ^ 2) = 5
answer
The width of the carpet is
5 feet
Answer:
the third one
Step-by-step explanation:
36+ 226h=425, I hope this helps:)
