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svetoff [14.1K]
3 years ago
14

If the area of square

Mathematics
1 answer:
koban [17]3 years ago
8 0

Answer:

Step-by-step explanation:

Square A:

Area = 225 square feet

side *side = 225

        Side =√225

                 =\sqrt{15*15}

   Side of square A = 15 ft

Square B:

Area = 400 square feet

Side =√400

       = \sqrt{20*20}

Side of square B = 20 ft

Use Pythagorean theorem for finding the side of Square C.

Side of square A is the altitude ;  side of square B is the base and side of square C will be the hypotenuse

hypotenuse² = base² + altitude²

                      = 15² + 20²

                       = 225 + 400

                       = 625

hypotenuse = \sqrt{625} =\sqrt{25*25} = 25 ft

Area of square C = 625 square ft

In short,

Area of square C = area of square B + area of square A

                             = 400 + 225

                             = 625 square ft

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snow_lady [41]
Because the time moved up by 15 minutes, we would already know that it would be (blank) megabytes per 15 minutes

75 megabytes - 15 megabytes = 60

this would mean 60 megabytes are downloaded per 15 minutes

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both of the answers above would be acceptable :)
7 0
3 years ago
Which inequality will have a dashed boundary line with a shaded area above its graph? 7x − y ≤ 3 x − y ≤ 4 2x − 9y > 2 4x + 7
alexdok [17]
Above the graph

look at them

7x-y <span><</span>3
x-y<span><</span>4
2x-9y>2
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dashed boundary line means it does't include htat means taat the symbol is < or >

cross out first 2

one way is to graph the lines as equations and shade accordingly

2x-9y>2
y<2/9x+2/9
shade on bottom

4x+7y>3
y>-7/4x+3/9
shade on top


aswer is 4x+7y>3
5 0
4 years ago
Select the functions that have a value of -1. sin180° cos180° tan180° csc180° sec180° cot180°
kupik [55]

We have to break each degree in terms of 90

A) sin180^\circ=sin(90\times2+0)

Which is in third quadrant, therefore sine is negative hence

sin(90\times2+0)= -sin0 ^\circ = 0


B) cos180^\circ =cos(90\times2+0)

Which is in third quadrant, therefore cosine is negative hence

cos(90\times2+0)= -cos0^\circ  = -1


C) tan180^\circ=tan(90\times2+0)

Which is in third quadrant, therefore tangent is positive hence

tan(90\times2+0)= tan0^\circ  = 0


D) csc180^\circ=csc(90\times2+0)

Which is in third quadrant, therefore cosec is negative hence

cosec(90\times2+0)= -csc0^\circ  =not defined


E)sec180^\circ=sec(90\times2+0)

Which is in third quadrant, therefore secant is negative hence

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F) cot180^\circ=cot(90\times2+0)

Which is in third quadrant, therefore tangent is positive hence

cot(90\times2+0)= cot0^\circ = not defined


Hence only cos 180^\circ and

sec180^\circ have value -1

Hope this will help

7 0
3 years ago
A certain component of an electronic device has a probability of 0.1 of failing. If there are 6 such components in a circuit, wh
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Answer:

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Step-by-step explanation:

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