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2 years ago

A local Pennysaver charges $11 for each of the first three lines of a classified ad, and $5 for each

Mathematics

2 answers:

krok68 [10]2 years ago

6 0

What’s the question?

choli [55]2 years ago

5 0

Step-by-step explanation:

a) $11 = 3 lines of a classified ad

$x = 2 limes of a classified ad

cross multiply

3x = 22

divide by the coefficient of x

which is 3

3x/3 = 22/3

x = 7.33 approximately 7

x = 7.

b) $11 = 3 lines of a classified ad

$x = 5 lines of a classified ad

cross multiply

3x = 55

diviee by the coefficient of x

which is 3

3x/3 = 55/3

x =18.33 approximately 18

x =18.

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The owner of a lemonade stand that costs 2 dollars per gallon with juice that costs 7 dollars per gallon. He gets 20 gallons of

Karo-lina-s [1.5K]

Answer:

Step-by-step explanation:

Your answer

62.222 gallons

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7 0

3 years ago

A farmer has 300 ft of fence to enclose 2 adjacent rectangular pens bordering his barn. Find the maximum area he can close.

Margarita [4]

Answer:

Width of 37.5 feet and length of 50 feet will maximize the area.

Step-by-step explanation:

Let w represent width and l represent length of the pen.

We have been given that a farmer has 300 ft of fence to enclose 2 adjacent rectangular pens bordering his barn. We are asked to find the dimensions that will maximize the area.

We can see from the attachment that the perimeter of the pens would be $4w+3l$ .

We can set our given information in an equation $4w+3l=300$ .

The area of the two pens would be $A=2l\cdot w$ .

From perimeter equation, we will get:

$w=\frac{300-3l}{4}$

Substituting this value in area equation, we will get:

$A=2l\cdot (\frac{300-3l}{4})$

Since we need to maximize area, so we need to find derivative of area function as:

$A=\frac{600l-6l^2}{4}$

Bring out the constant:

$A=\frac{1}{4}*\frac{d}{dl}(600l-6l^2)$

$A=\frac{1}{4}*(600-12l)$

$A=150-3l$

Now, we will set our derivative equal to 0 as:

$150-3l=0$

$150=3l$

$\frac{150}{3}=\frac{3l}{3}$

$50=l$

Now, we will substitute $l=50$ in equation $w=\frac{300-3l}{4}$ to solve for width as:

$w=\frac{300-3(50)}{4}$

$w=\frac{300-150}{4}$

$w=\frac{150}{4}$

$w=37.5$

Therefore, width of 37.5 feet and length of 50 feet will maximize the area.

8 0

3 years ago

HELP!! Please answer 9 and ten with solution needed!!

sashaice [31]

Answer:

m=7 z=-12

Step-by-step explanation:

expand brackets:

8m+24=5m+45

Change sides:

8m-5m=45-24

3m=21

m=7

z-6 = 3

2z 4

Coss multiply:

4z-24=6z

4z-6z=24

-2z=24

Divide both sides by -2:

z=-12

4 0

1 year ago

Describe the vector that defined the following translation. HELPPPPP RNN

siniylev [52]

Answer:

t.uy

Step-by-step explanation:

3 0

1 year ago

The ratio of credit card sales to cash sales at a store was 8:3. If the store had 144 cash sales, how many more credit card sale

Neko [114]

Answer:

There were 240 more credit card sales than cash sales.

Step-by-step explanation:

By using the ratio 8:3 I was able to determine that if there were 144 cash sales that would mean that there would be 384 credit card sales. However, the question asks "How many more credit card sales were there than cash sales?" Meaning that we need to find the difference. 384-144= 240.

This means that there were 240 more credit card sales than cash sales.

Hope this helped! If you have any questions about what I did please comment!

And if this helped please mark brainliest!

Have a great day!!

4 0

2 years ago