Answer:
12m
Step-by-step explanation
If the height of the ball after x seconds be modelled by the equation
h(x)=−(x−2)² +16
The height of the ball at the time it is thrown will be the height at the initial time. At that point that it is initially thrown the time is 0seconds i.e x = 0
To get the height at t x = 0seconds, we will substitute x = 0 into the modeled function to have;
h(0) = -(-0-2)²+16.
h(0) = -(-2)²+16
h(0) = -4+16
h(0) = 12
The height of the ball at the time the ball is thrown is 12m
Easy Algebra question!
Let's use "x" as a variable.
The equation would be x+x+60 = 240 with "x" being George's weight.
Subtract 60 from both sides and you get 2x = 180.
From there you divide both sides by 2, getting x=90.
"x" is George's weight, so he weighs 90 pounds.
ANSWER: 90 POUNDS
Answer:
5 miles
Step-by-step explanation:
14 - 8.37 means his car still had 5.63 gallons
27.6/5.63 = 4.9
He can make a 70 or higher to keep a B avg.
