Answer:
The length of the sunken vessel, to the nearest tenth is 200 m
Step-by-step explanation:
The given information are;
The depth of the sunken vessel below the ship = 120 m
The angle of depression to the front of the sunken vessel = 55°
The angle of depression to the back of the sunken vessel = 46°
Therefore, we have;
The length, A, of the from directly below the ship to the front of the sunken vessel given as follows;
Tan(55°) = ((120 m)/A)
A = 120 / Tan(55°) ≈ 84.025 m
The length, B, of the from directly below the ship to the back of the sunken vessel given as follows;
tan(46°) = ((120 m)/B)
B = 120 / tan(46°) ≈ 115.88 m
The length, L, of the sunken vessel = A + B
L = A + B = 120 / Tan(55°) + 120 / tan(46°) ≈ 84.025 m + 115.88 m ≈ 199.91 m
∴ The length, L, of the sunken vessel, to the nearest tenth = 200 m.
