I need help please
1 answer:
You might be interested in
Answer:
Step-by-step explanation:
Distribute:
Combine like terms:
-2r + 4 is your answer.
Answer:
The group's claim is not supported at 1% significance level.
Step-by-step explanation:
given that a local group claims that the police issue more than 60 speeding tickets a day in thire area
The data they collected for 2 weeks is given below:
70 48 41 68 69 55 70
57 60 83 32 60 72 58
Std error of mean =
(Right tailed test at 1% significance level)
Mean difference = 0.10
Test statistic t with df 13 = mean difference/std error
= 0.029
p value = 0.4886
Since p >0.01, we accept null hypothesis
The group's claim is not supported at 1% significance level.
Answer:
a. X~N(2,885, 651)
b. 0.086291
c. 0.00058
d. 3213.10 calories
Step-by-step explanation:
a. -A normal distribution is expressed in the form X~N(mean, standard deviation).
-Let X a random variable denoting the number of calories consumed.
-X is a is a normally distributed random variable with mean 2885 and standard deviation 651.
-This distribution is expressed as X~N(2,885, 651)
b. The probability that less than 2000 calories are consumed is calculated using the formula:
#substitute the given values in the formula to solve for P:
Hence, the probability of consuming less than 2000 calories is 0.08691
c. The proportion of customers consuming more than 5000 calories is calculated as:
Hence, the proportion of customers consuming over 5000 calories is 0.00058
d. The least amount of calories to get the award is calculated as:
1% is equivalent to a z value of 0.50399.
-We equate this to the formula to solve for the mean consumption:
Hence, the least amount of calories consumed to qualify for the award is 3213.10 calories.