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Juliette [100K]
3 years ago
7

Find three consecutive odd integers such that the square of the second decreased by four times the first is seven more than six

times the third.
please help
Mathematics
1 answer:
pentagon [3]3 years ago
5 0

Answer:

x, x+2, x+4

(x+2)^2 - 4(x) = 6(x + 4) + 7

x^2 + 4x + 4 - 4x = 6x + 24 + 7

x^2 - 6x - 27 = 0

x = 9 (∨ x = -3)

The three numbers are

9, 11, 13

but it could be also

-3, -1, 1

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Calculate the rate of change from the graph below
qaws [65]

Answer:

The rate of change is 0.75 gallons per minute

Step-by-step explanation:

The rate of change of the linear relation is represented by the slope of the line which represents this relation

The rule of the slope of a line is

m = Δy/Δx, where

  • Δy is the vertical change
  • Δx is the horizontal change

From the given graph

∵ The line passes through points (0, 0) and (4, 3)

∴ Δx = 4 - 0 = 4

∴ Δy = 3 - 0 = 3

→ Use the rule of the slope above to find the slope of the line

∴ m = \frac{3}{4} = 0.75

∵ The x-axis represents the time in minutes

∵ The y-axis represents the amount in gallons

∵ m represents the rate of change

∴ The rate of change = 0.75 gallons per minute

7 0
3 years ago
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belka [17]
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3 0
3 years ago
Given h(t)=-2(t+5)2 , find h(-8)
amm1812
The answer I got was 12 if needed I can take a picture of how I worked it

5 0
3 years ago
Which of these skills do you think you could teach someone else select all that apply
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3 years ago
Find the average value of the function on the given interval.<br> f(x)=ex/7; [0,7]
Anastaziya [24]

Answer:

f_{avg}=e-1

Step-by-step explanation:

We are given that a function

f(x)=e^{\frac{x}{7}}

We have to find the average value of function on the given interval [0,7]

Average value of function on interval [a,b] is given by

\frac{1}{b-a}\int_{a}^{b}f(x)dx

Using the formula

f_{avg}=\frac{1}{7-0}\int_{0}^{7}e^{\frac{x}{7}} dx

f_{avg}=\frac{1}{7}[e^{\frac{x}{7}}\times 7)]^{7}_{0}

By using the formula

\int e^{ax}=\frac{e^{ax}}{a}

f_{avg}=(e-e^0)=e-1

Because e^0=1

f_{avg}=e-1

Hence, the average value of function on interval [0,7]

f_{avg}=e-1

8 0
3 years ago
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