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Juliette [100K]

3 years ago

7

Find three consecutive odd integers such that the square of the second decreased by four times the first is seven more than six

times the third.
please help

1 answer:

pentagon [3]3 years ago

5 0

Answer:

x, x+2, x+4

(x+2)^2 - 4(x) = 6(x + 4) + 7

x^2 + 4x + 4 - 4x = 6x + 24 + 7

x^2 - 6x - 27 = 0

x = 9 (∨ x = -3)

The three numbers are

9, 11, 13

but it could be also

-3, -1, 1

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Answer:

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2 years ago

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2 years ago

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Step-by-step explanation:

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3 years ago

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grin007 [14]

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Step-by-step explanation:

You need to remember that:

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2 years ago