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Juliette [100K]
3 years ago
7

Find three consecutive odd integers such that the square of the second decreased by four times the first is seven more than six

times the third.
please help
Mathematics
1 answer:
pentagon [3]3 years ago
5 0

Answer:

x, x+2, x+4

(x+2)^2 - 4(x) = 6(x + 4) + 7

x^2 + 4x + 4 - 4x = 6x + 24 + 7

x^2 - 6x - 27 = 0

x = 9 (∨ x = -3)

The three numbers are

9, 11, 13

but it could be also

-3, -1, 1

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Express this number in scientific notation.<br> 78 million
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7.8 x 10^7

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Halla el conjunto solución del siguiente sistema de ecuaciones aplicando el método de reducción: 2x + 3y = 8 x – 5y = 6
AysviL [449]

Answer:

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Step-by-step explanation:

Given that,

Two equations,

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