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tester [92]
2 years ago
9

What is the sum of the 2nd square number and the 2nd cube number?

Mathematics
1 answer:
hammer [34]2 years ago
8 0

Answer:

17

Step-by-step explanation:

Second square number is 9; 3×3

second cube number is 8; 2×2×2

9+8=17.

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The set of integers greater than 50
UkoKoshka [18]
The set of integers greater than 50 are (51,52,53,54...)
5 0
3 years ago
In the given figure △ABC ≅△DEC. Which of the following relations can be proven using CPCTC ?
Serhud [2]

Option B:

\overline{A B}=\overline{D E}

Solution:

In the given figure \triangle A B C \cong \triangle D E C.

If two triangles are similar, then their corresponding sides and angles are equal.

By CPCTC, in \triangle A B C \ \text{and}\ \triangle D E C,

\overline{AB }=\overline{DE} – – – – (1)

\overline{B C}=\overline{EC} – – – – (2)

\overline{ CA}=\overline{CD} – – – – (3)

\angle ACB=\angle DCE  – – – – (4)

\angle ABC=\angle DEC  – – – – (5)

\angle BAC=\angle EDC  – – – – (6)

Option A: \overline{B C}=\overline{D C}

By CPCTC proved in equation (2) \overline{B C}=\overline{EC}.

Therefore \overline{B C}\neq \overline{D C}. Option A is false.

Option B: \overline{A B}=\overline{D E}

By CPCTC proved in equation (1) \overline{AB }=\overline{DE}.

Therefore Option B is true.

Option C: \angle A C B=\angle D E C

By CPCTC proved in equation (4) \angle ACB=\angle DCE.

Therefore \angle A C B\neq \angle D E C. Option C is false.

Option D: \angle A B C=\angle E D C

By CPCTC proved in equation (5) \angle ABC=\angle DEC.

Therefore \angle A B C\neq \angle E D C. Option D is false.

Hence Option B is the correct answer.

\Rightarrow\overline{A B}=\overline{D E}

5 0
3 years ago
2x greater than of equal to -2/3x(4x+4)
ryzh [129]

x  \geqslant  -  \frac{1}{ {12x}^{2} + 12x }
(I can be wrong.)
7 0
3 years ago
Will give brainliest and add more points to your acc if good awnser Please help ASAP
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Hailey's mixing two different coffee blends.  Represent them by x and y (in pounds).  Then x + y = 5 lb, and x = 5 - y.How much puree Sum. beans are we talking about here?
0.20x +0.80y = 0.60(5 lb)  Mult all 3 terms by 100 to get rid of factions:
20x + 80 y = 300.  Substitute 5-y for x:
20(5-y) + 80y = 300 => 100-20y + 80y = 300 => 60y = 200,  so                                                                                  y = 20/6 or 10/3 lb                                              den x = 5-10/3, or    x =5/3 lb
Use 5/3 lb of the first blend and 10/3 lb of the second blend to come up with 5 lb of a 60% blend.
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Please help hurry! ty
MAXImum [283]

Answer:

....

Step-by-step explanation:

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3 years ago
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