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tester [92]
2 years ago
9

What is the sum of the 2nd square number and the 2nd cube number?

Mathematics
1 answer:
hammer [34]2 years ago
8 0

Answer:

17

Step-by-step explanation:

Second square number is 9; 3×3

second cube number is 8; 2×2×2

9+8=17.

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The chance of rain is 20%, the chance of it being sunny is 60%, and the chance of it
Charra [1.4K]

Answer:

0.6 = 60% probability that it is either sunny or rainy.

Step-by-step explanation:

We solve this question treating these events as Venn probabilities.

I am going to say that:

Event A: Rain

Event B: Sun

The chance of rain is 20%

This means that P(A) = 0.2

The chance of it being sunny is 60%

This means that P(B) = 0.6

The chance of it being sunny and rainy at the same time is 10%.

This means that P(A \cap B) = 0.1

Calculate, the probability that it is either sunny or rainy.

This is:

P = P(A) + P(B) - 2P(A \cap B) = 0.2 + 0.6 - 0.2 = 0.6

0.6 = 60% probability that it is either sunny or rainy.

3 0
3 years ago
You have a collection of 30 coins, all of which are dimes and quarters. The total of your collection is $5.10 how many of each k
aksik [14]
14 quarters and 16 dimes
I think ?





8 0
3 years ago
The question is.......
Hunter-Best [27]

multiply the 2 numbers together than divide by 2

7 1/2 = 15/2

12 2/3 = 38/3

15/2 * 38/3 = 570/6 =95

95/2=47.5 square feet

5 0
4 years ago
Read 2 more answers
WILL AWARD BONUS POINTS FOR A GOOD ANSWER! URGENT! Justin's sand castle is 180 cm tall but the wind is blowing away sand at a ra
mote1985 [20]

Answer:

I think around 17 min...

Step-by-step explanation:

there is 60 sec in a minute so divide 60/8 , divide 60/6, then add them together....

60/8= 7.5 and 60/ 6=10

so 7.5+10 = 17.5

somewhere around there

6 0
4 years ago
You roll two fair dice, a green one and a red one. (a) What is the probability of getting a sum of 6? (Enter your answer as a fr
Stels [109]

Answer:

5/36 ; 1/12 ; 2/9 ; yes

Step-by-step explanation:

Given the following :

Roll of two fair dice : green and red

Probability = (number of required outcomes / number of total possible outcomes)

(a) What is the probability of getting a sum of 6?

Number of required outcomes = 5

P(sum of 6) = 5/36

b.) What is the probability of getting a sum of 10?

Number of required outcomes = 3

P(sum of 10) = 3 / 36 = 1/12

c.) What is the probability of getting a sum of 6 or 10?

P(getting a sum of 6) + P(getting a sum of 10)

(5/36) + (1/12) = (5 + 3) / 36

= 8/36 = 2/9

The events are mutually exclusive because each event cannot occur at the same time.

8 0
4 years ago
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