You know from trigonometry that AB = 15 units, so the area of the larger triangle ACB is (1/2)*15*15 = 112.5 units^2.
Then the area of triangle ADE is
.. (112.5 -62.5) = 50 . . . . units^2
Answer:
The answer is 184.7 ft
Step-by-step explanation:
You need to find the distance from kite to ground
sin38°/1 = x/300
x = 300 · sin 38
Therefore your answer is 184.7
This is the best way I could explain it....Hope this helps:)
RS is 68 and T is 92 if you want an explanation then i gotten but u said quick so maybe it is timed idk
4(-2)-3 = -8-3 = -11
Answer: -11
The linked answer is wrong because that integral gives you the net displacement of the object, not the total distance.
To get the distance, you have to integrate the speed (as opposed to velocity), which involves integrating the absolute value of the velocity function.

By definition of absolute value,

Over this particular integration interval,
• sin(<em>t</em> ) ≥ 0 for 1 ≤ <em>t</em> < <em>π</em>, and
• sin(<em>t</em> ) < 0 for <em>π</em> < <em>t</em> ≤ 5
so you end up splitting the integral at <em>t</em> = <em>π</em> as

Now compute the distance:



making B the correct answer.