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Sindrei [870]
2 years ago
6

Need help with this asap!!

Mathematics
2 answers:
Mamont248 [21]2 years ago
8 0

Answer:

Hence its true.

Explanation:

a + b = c   [ equation 1 ]

b = x          [ equation 2 ]

solve:

replace b with x as they are equal.

a + x = c

Valentin [98]2 years ago
3 0
<h2>I think the answer is True </h2>

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Mark bought 4 pounds of apples for 7.56 what was the cost per pound
marusya05 [52]

Answer:

1.89

Step-by-step explanation:

7.56 ÷ 4 = 1.89

3 0
3 years ago
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Which of the following is the volume of a square pyramid with a base of 6 in and a height of 7 in?
Karolina [17]
Volume = 1/3*a^2*h
So, V = (36*7)/3
          = 84
3 0
3 years ago
Make 2 equations for this geometric sequence:<br> 36, 18, 9, 4.5, 2.25, 1.125, 0.5625, 0.28125...
NNADVOKAT [17]
I think the answer will be .5
3 0
3 years ago
The area of ABED is 49 square units. Given AGequals9 units and ACequals10 ​units, what fraction of the area of ACIG is represent
Mrac [35]

Answer:

The fraction of the area of ACIG represented by the shaped region is 7/18

Step-by-step explanation:

see the attached figure to better understand the problem

step 1

In the square ABED find the length side of the square

we know that

AB=BE=ED=AD

The area of s square is

A=b^{2}

where b is the length side of the square

we have

A=49\ units^2

substitute

49=b^{2}

b=7\ units

therefore

AB=BE=ED=AD=7\ units

step 2

Find the area of ACIG

The area of rectangle ACIG is equal to

A=(AC)(AG)

substitute the given values

A=(9)(10)=90\ units^2

step 3

Find the area of shaded rectangle DEHG

The area of rectangle DEHG is equal to

A=(DE)(DG)

we have DE=7\ units

DG=AG-AD=9-7=2\ units

substituteA=(7)(2)=14\ units^2

step 4

Find the area of shaded rectangle BCFE

The area of rectangle BCFE is equal to

A=(EF)(CF)

we have

EF=AC-AB=10-7=3\ units

CF=BE=7\ units

substitute

A=(3)(7)=21\ units^2

step 5

sum the shaded areas

14+21=35\ units^2

step 6

Divide the area of  of the shaded region by the area of ACIG

\frac{35}{90}

Simplify

Divide by 5 both numerator and denominator

\frac{7}{18}

therefore

The fraction of the area of ACIG represented by the shaped region is 7/18

5 0
3 years ago
Find the inverse of g(x) = 3x^2 - 5
Arte-miy333 [17]

Answer:

\boxed{\sf \ \ \ g^{-1}(x)=\sqrt{\dfrac{x+5}{3}} \ \ \ }

Step-by-step explanation:

Hello,

x=(gog^{-1})(x)=g(g^{-1}(x))=3(g^{-1}(x))^2-5\\\\3(g^{-1}(x))^2 = x+5\\\\\\ (g^{-1}(x))^2=\dfrac{x+5}{3}\\g^{-1}(x)=\sqrt{\dfrac{x+5}{3}}

hope this helps

8 0
3 years ago
Read 2 more answers
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