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serg [7]
2 years ago
12

What is 389/1000 converted into a decimal

Mathematics
2 answers:
V125BC [204]2 years ago
7 0

Answer:

389/1000

0.00389

Step-by-step explanation:

neonofarm [45]2 years ago
6 0

Answer:46.000

Step-by-step explanation:

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What number is 10times bigger than 30​
barxatty [35]

Answer:

300

Step-by-step explanation:

30 * 10 = 300

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Solve this system of equations:<br><br><br><br> What is the value of x?
Ipatiy [6.2K]

Answer:

2

Step-by-step explanation:

Substitute y=2x in the first equation into the second.

The second equation then becomes;

x = -(2x)+6

x = -2x+6

Collectiing like terms, more -2x to the left,

x+2x =6

3x=6

x=\frac{6}{3}

x= 2

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2 years ago
Along which axis is the dependent variable traditionally plotted?
Dvinal [7]
The y axis for dependent variables and x axis for independent
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3 years ago
How do you get the volume of a triangular prism?
lisov135 [29]
The equation for that is V = 1/2 A x C x H
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2 years ago
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This is for algebra 2 can someone tell me if I’m right and can someone explain how do you get a= ?
algol13

Answers:

a = 2

h = 3

k = -3

You have the correct h and k values. Nice work so far.

==========================================================

Explanation:

(h,k) is the vertex. So (h,k) = (3,-3) meaning h = 3 and k = -3

To get the value of 'a', we need to plug in some point on the red graph. Each point is of the form (x,y). We can pick any point we want that isn't the vertex.

Let's pick (0,3) which is the y intercept. I'm picking this because 0 is an easy number to work with

------------

y = a|x-h| + k

y = a|x-3| + (-3) .... plug in the h,k values

y = a|x-3| - 3

3 = a|0-3| - 3 .... plug in (x,y) = (0,3)

3 = a|-3| - 3

3 = a*3 - 3

3 = 3a - 3

3a-3 = 3

3a = 3+3 ... adding 3 to both sides

3a = 6

a = 6/3 ... divide both sides by 3

a = 2

The value a = 2 indicates that the parent function y = |x| has been stretched vertically by a factor of 2. So it is twice as tall as before. Then it has been shifted to place the vertex at (3,-3) as shown in the graph.

------------

You may be wondering why you can't pick on the vertex for (x,y)

Let's see what happens if we use (x,y) = (3,-3)

y = a|x-3| - 3

-3 = a|3-3| - 3 ... plug in (x,y) = (3,-3)

-3 = a|0| - 3 ... uh oh, we get 0 here

-3 = a*0 - 3

-3 = 0 - 3

-3 = -3

We get a true statement, which is nice, but it doesn't tell us anything about what the value of 'a' is. That 'a' term goes away entirely. So I avoided using x = 3 to prevent x-3 from being 0.

4 0
3 years ago
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