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3 years ago

WILL GIVE BRAINLIEST!

Mathematics

1 answer:

gayaneshka [121]3 years ago

8 0

Answer:

16 yards

Step-by-step explanation:

Using the formula

A=hb/2

Solving forb

b=2A/hb=2·72

9=16yd

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I need help dont get it

Mariulka [41]

Answer:

a.) y= 25 + 5x

b.) 45$

Step-by-step explanation:

25$ from the start and adds 5 for extra

y= 25+5(4)

y=25+20

y=45$

7 0

3 years ago

Write an equation of the line below.

tamaranim1 [39]

Answer: y = -3/4x

Step-by-step explanation:

the slope is -3/4

4 0

3 years ago

Read 2 more answers

Help i will give 20 points<br> And brainlist

marysya [2.9K]

Answer:

for #14, x=10

Step-by-step explanation:

in the graph, 6x = 5x +10 so if x was 10 it would be 60 = 60 so x = 10

5 0

3 years ago

The weights of items produced by a company are normally distributed with a mean of 4.5 ounces and a standard deviation of 0.3 ou

GalinKa [24]

Answer:

The right solution is:

(a) 0.8849

(b) 12.28%

(c) 4.9935

(d) 28004

Step-by-step explanation:

Given:

Mean,

= 4.5

Standard deviation,

= 0.3

(a)

P(x > 4.14)

As we know,

⇒ $z = \frac{4.14-4.5}{0.3}$

$=-1.20$

then,

⇒ $P(z>-1.20) = P(z$

$=0.8849$

(b)

P(4.8 < x < 5.04)

= $P(\frac{4.8-4.5}{0.3} < \frac{x-\mu}{\sigma} < \frac{5.04-4.5}{0.3} )$

= $P(1$

= $P(z$

= $0.9641 -0.8413$

= $0.1228$

or,

= $12.28$ (%)

(c)

P(x > x) = 0.05

z value will be,

= 1.645

⇒ $1.645 = \frac{x - 4.5}{0.3}$

$x = 4.9935$

(d)

P(x < 5.01)

⇒ $z = \frac{x- \mu}{\sigma}$

$=\frac{5.01-4.5}{0.3}$

$=1.7$

P(z < 1.70) = 0.9554

⇒ $n = \frac{27875}{0.9954}$

$=28004$

3 0

3 years ago

used to flavor vanilla ice cream and other foods) is the substance whose aroma the human nose detects in the smallest amount. Th

lubasha [3.4K]

Answer:

The cost to supply enough vanillin so that the aroma could be detected in a large aircraft hangar with a volume of 5.95 x 10^7 ft^3 is $ 0.07.

Step-by-step explanation:

The volume of the hangar is

$V=5.95*10^7 \, ft^3$

The minimal amount of vainilla needed to be detected in the hangar is equivalent to the threshold multiplied by the volume of the hangar:

$Va=V*Th=5.95*10^7 \, ft^3*2.0*10^{-11}\,\frac{g}{L}*\frac{28.317L}{1ft^3}\\ \\Va=336.9723*10^{-4} \, g=0.0337\,g$

The cost of this amount of vainilla is

$Cost = Va*p=0.0337\,g*\frac{104\, usd}{50\, g} =0.07 \, usd$

The cost to supply enough vanillin so that the aroma could be detected in a large aircraft hangar with a volume of 5.95 x 10^7 ft^3 is $ 0.07.

5 0

4 years ago