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3 years ago

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What is the equation of a line that is parallel to −3x+4y=4 and passes through the point (4, 0) ?

1 answer:

sladkih [1.3K]3 years ago

4 0

Hey!

So the first thing you want to do is put the line that you are given in slope-intercept form so that we can find the slope of the line parallel to it. Two lines that are parallel will always have the same slope. So lets start by changing the format of the equation:

-3x + 4y = 4

4y = 3x + 4

y = (3/4)x + 1

Now that we have the equation in slope-intercept form we can see that the slope of the line parallel to this is 3/4. So we already know the slope of the line and a point on the line. We can now plug this point into the equation y = mx + b. Since we also know the slope we can plug that in as well.

0 = (3/4)(4) + b

0 = 3 + b

-3 = b

Now that we know the y-intercept you can plug that and the slope into the y=mx + b equation to get your answer:

y = (3/4)x - 3

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skelet666 [1.2K]

Answer:

$xe^x+5e^x$

Step-by-step explanation:

We have given integral $\int (x+6)e^xdx$

$\int (xe^x+6e^x)dx$

$\int (I_1+I_2)dx$ , here $I_1=xe^x$ and $I_2=6e^x$

Now first integrate $I_1$

So $I_1=\int xe^x$

Integrating by part

$I_1=x\int e^x-\int e^x\frac{d}{dx}x$

$I_1=x e^x- e^x$

$I_2=6\int e^x=6e^x$

So $I=I_1+I_2=xe^x-e^x+6e^x=xe^x+5e^x$

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3 years ago

17 1/4 over 100 as a decimal

Andrew [12]

Answer:

0.1725

Step-by-step explanation:

17 1/4 /100

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2 years ago

Read 2 more answers

X=16-4y. systems of equations 3x+4y=8<br> substitution

alina1380 [7]

Answer:

x=-4 y=5

Step-by-step explanation:

Rewrite equations:

x=−4y+16;3x+4y=8

Step: Solvex=−4y+16for x:

x=−4y+16

Step: Substitute−4y+16forxin3x+4y=8:

3x+4y=8

3(−4y+16)+4y=8

−8y+48=8(Simplify both sides of the equation)

−8y+48+−48=8+−48(Add -48 to both sides)

−8y=−40

−8y

−8

=

−40

−8

(Divide both sides by -8)

y=5

Step: Substitute5foryinx=−4y+16:

x=−4y+16

x=(−4)(5)+16

x=−4(Simplify both sides of the equation)

Answer:

x=−4 and y=5

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2 years ago

SinA=√1-x÷√1+X<br> Find the value of cosA

Irina-Kira [14]

The value of cos A is √(1 + x²)/ (1 - x²) /√1 + x

<h3>Trigonometric ratios</h3>

It is important to note that

sin A = opposite/ hypotenuse

cos A = adjacent/ hypotenuse

Then,

opposite = $\sqrt{1} - x$

Hypotenuse = $\sqrt{1} + x$

Let's find the adjacent side using the Pythagorean theroem

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$cos A = \frac{\sqrt{\frac{1+x^2}{1 -x^2} } }{\sqrt{1} +x}$

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Thus, the value of cos A is √(1 + x²)/ (1 - x²) /√1 + x

Learn more about trigonometric identities here:

brainly.com/question/7331447

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1 year ago

What is the inverse of the function f(x) = 2x – 10

BartSMP [9]

Answer:

y = 1/2x +5

Step-by-step explanation:

change f(x) to y

y = 2x - 10

then switch x and y

x = 2y - 10

then solve for y

add 10 to both sides and divide both sides by 2

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2 years ago

Read 2 more answers