Answer:
After finding the prime factorization of $2010=2\cdot3\cdot5\cdot67$, divide $5300$ by $67$ and add $5300$ divided by $67^2$ in order to find the total number of multiples of $67$ between $2$ and $5300$. $\lfloor\frac{5300}{67}\rfloor+\lfloor\frac{5300}{67^2}\rfloor=80$ Since $71$,$73$, and $79$ are prime numbers greater than $67$ and less than or equal to $80$, subtract $3$ from $80$ to get the answer $80-3=\boxed{77}\Rightarrow\boxed{D}$.
Step-by-step explanation:
hope this helps
Answer:
The positive solution is 2.4.
Step-by-step explanation:
The given functions are


It is given that




The quadratic formula:







Therefore the positive solution is 2.4.
<h3>
Answer: They're all the same</h3>
====================================================
Reason:
means we have 6 copies of "2" multiplied out as shown in choice B. That explains how A and B are the same, and we can say

The parenthesis are optional, but I find they're handy to count the '2's easier.
----------------
Now notice that

So,

The last step is possible because we have two copies of
multiplied together.
This shows that choice C is equivalent to A and B.
-------------------
Lastly,

The jump to the last step is possible because we have three copies of
multiplied together.
This shows choice D is equivalent to the others.
All four expressions are the same.
They represent different ways to say the same number. That number being 64.
Answer:
B) y = 7x
Step-by-step explanation:
Start with:

Substitute in two points from the graph.
(Let's use (8,56) & (16,112)

Combine like terms.

Simplify.
