The education is (x-h)^2 + k ands the vertex is (h,k)
<u>Answer:</u>
Angle A = 39°
<u>Step-by-step explanation:</u>
We are given that there is a triangle ABC where a = 9, c = 5 and angle B = 120° and we are to find the measure of angle A.
But first we need to find the side b using the law of cosine:



Now finding angle A using law of cosine:




Therefore, the measure of angle A = 39°.
Answer:
Nine less than twice a number 2x-9
Seven divided by a number 7-x
Ninety-nine plus the difference of eleven and five 99+(11-5)
Four-fifths more than three times. Number 3x+4/5
Step-by-step explanation:
Please mark brainliest
i believe your answer will be 0.04 or 4/100
OR if you need an equivalent expression, that would be 81/2187