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2 years ago

Help me cuh PLEASE ..

Mathematics

1 answer:

DochEvi [55]2 years ago

7 0

Answer:

I'm so sorry but I'm not really sure myself ! I hope you get or found the answer already.

Step-by-step explanation:

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Evaluate the expression when g = 6 and h=34. h-5g

UNO [17]

Answer:

Step-by-step explanation:

if g is 6 and h is 34 then h-5g is equal to

34-5×6=34-30=4

have a nice day

3 0

3 years ago

Read 2 more answers

Could someone assist me with this?

Blababa [14]

Answer:

Step-by-step explanation:

Formula for Area of a parallelogram: A = bh

So multiply the base (25cm) by the height (16cm) to get 400cm^2.

Volume formula l x w x h

Multiply the length of the pool (20ft) by the width (15ft) by the height (6ft) to get 1,800ft^2

Formula for Area of a trapezoid A= a+b/2 * h

Where a is (12.6in), b is (15in), and h is (3.4in) just plug in the numbers into the formula to get 46.92in^2

Same thing as number one, use the Area of a parallelogram formula A = bh

6 0

2 years ago

1) find the equation of the line parallel to

In-s [12.5K]

Answer:

1) The equation of the line parallel to x-5y=6 and through (4,-2) is 5y = x -14

2) The equation of the line perpendicular to y= -2/5x + 3 and through (2,-1) is 2y = 5x -12

Solution:

1) find the equation of the line parallel to x-5y=6 and through (4,-2).

Given, line equation is x – 5y = 6

We have to find the line equation that is parallel to given line and passing through the point (4, -2)

Now, let us find slope of the given line.

$\text { Slope }=\frac{-x \text { coefficient }}{y \text { coefficient }}=\frac{-1}{-5}=\frac{1}{5}$

Now, we know that, slope of parallel lines are equal.

So, slope of required line is 1/5 and it passes through (4, -2)

Now, using point slope form

$y-y_{1}=m\left(x-x_{1}\right) \text { where } m \text { is slope and }\left(x_{1}, y_{1}\right) \text { is point on line. }$

$y-(-2)=\frac{1}{5}(x-4) \rightarrow 5(y+2)=x-4 \rightarrow 5 y+10=x-4 \rightarrow x-5 y=14$

Hence, the line equation is 5y = x -14

2) find the equation of the line perpendicular to y= -2/5x + 3 and through (2,-1)

$\text { Given, line equation is } y=-\frac{2}{5} x+3 \rightarrow 5 y=-2 x+15 \rightarrow 2 x+5 y=15$

We have to find the line equation that is perpendicular to given line and passing through the point (2, -1)

Now, let us find slope of the given line.

$\text { Slope }=\frac{-x \text { coefficient }}{y \text { coefficient }}=\frac{-2}{5}=-\frac{2}{5}$

Now, we know that, product of slopes of perpendicular lines equals to -1.

So, slope of required line $\times$ slope of given line = -1

slope of required line = $-1 \times \frac{5}{-2}=\frac{5}{2}$

And it passes through (2, -1)

Now, using point slope form

$\begin{array}{l}{\text { Line equation is } y-(-1)=\frac{5}{2}(x-2) \rightarrow 2(y+1)=5(x-2)} \\\\ {\rightarrow 2 y+2=5 x-10 \rightarrow 5 x-2 y=12}\end{array}$

Hence, the line equation is 2y = 5x -12

4 0

3 years ago

When they go to the movies the Herandez family uses the formula 4,50C + 9,75A=T determine the total cost of their evening

r-ruslan [8.4K]

Their total cost of their evening is $14.15

8 0

3 years ago

Simplify 3 : 18 the following in to the form 1 : n

vekshin1

Answer:

1 : 6

Step-by-step explanation:

3 : 18

3 ÷ 3 : 18 ÷ 3

1 : 18 ÷ 3

1 : 6

7 0

3 years ago

Read 2 more answers