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2 years ago

Brainliest if you finish fast and simple and if correct!!!!!!!!!

Mathematics

2 answers:

notsponge [240]2 years ago

7 0

Mark the other user as brainliest!

iren [92.7K]2 years ago

3 0

Answer:

1. 8

2. 8 calories

3. 125 lb

Step-by-step explanation:

From inspection of the graphs

1. x ≥ 125 = 8

2. 8 calories

3. 125 lb

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What is the difference? StartFraction x Over x squared minus 16 EndFraction minus StartFraction 3 Over x minus 4 EndFraction Sta

katovenus [111]

Answer:

The option "StartFraction negative 2 (x + 6) Over (x + 4) (x minus 4) EndFraction" is correct

That is $\frac{-2(x+6)}{(x+4)(x-4)}$

Therefore $\frac{x}{x^2-16}-\frac{3}{x-4}=\frac{-2(x+6)}{(x+4)(x-4)}$

Step-by-step explanation:

Given problem is StartFraction x Over x squared minus 16 EndFraction minus StartFraction 3 Over x minus 4 EndFraction

It can be written as below :

$\frac{x}{x^2-16}-\frac{3}{x-4}$

To solve the given expression

$\frac{x}{x^2-16}-\frac{3}{x-4}$

$=\frac{x}{x^2-4^2}-\frac{3}{x-4}$

$=\frac{x}{(x+4)(x-4)}-\frac{3}{x-4}$ ( using the property $a^2-b^2=(a+b)(a-b)$ )

$=\frac{x-3(x+4)}{(x+4)(x-4)}$

$=\frac{x-3x-12}{(x+4)(x-4)}$ ( by using distributive property )

$=\frac{-2x-12}{(x+4)(x-4)}$

$=\frac{-2(x+6)}{(x+4)(x-4)}$

$\frac{x}{x^2-16}-\frac{3}{x-4}=\frac{-2(x+6)}{(x+4)(x-4)}$

Therefore $\frac{x}{x^2-16}-\frac{3}{x-4}=\frac{-2(x+6)}{(x+4)(x-4)}$

Therefore the option "StartFraction negative 2 (x + 6) Over (x + 4) (x minus 4) EndFraction" is correct

That is $\frac{-2(x+6)}{(x+4)(x-4)}$

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Step-by-step explanation:

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3 years ago

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3 years ago

HELP Find the area of the polygon with the vertices of A(2,2), B(2,7), C(8,7),and D(4,2)

Illusion [34]

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3 years ago

3(x-6) + 4 + 5x - 6 (use distributive property) please help asap!

Dmitry_Shevchenko [17]

Answer:

8x - 20

Step-by-step explanation:

3(x - 6) + 4 + 5x - 6 $\longmapsto$ Distribute 3 to (x - 6)

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3 years ago

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