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Brut [27]
2 years ago
15

An Account grows at an annual interest rate, it grows by a factor of x=1 + r each year. The function A(x)=800x^4 + 350x^3 + 500x

^2 + 600x gives the amount in the account after 4 years when the growth factor is x.
After 5 years, $200 is added to the account. Use the expression for A(x) to write a new expression B(x) that represents how much is in the account after 5 years.
Mathematics
2 answers:
Marina86 [1]2 years ago
7 0

Answer:

Applying the formula, it is found that the total amount in the account will be of $2,431.3. I THINK

Step-by-step explanation:

IM NOT SURE!

lys-0071 [83]2 years ago
6 0

Answer:

Applying the formula, it is found that the total amount in the account will be of $2,431.3. I THINK

Step-by-step

Applying the formula, it is found that the total amount in the account will be of $2,431.3. I THINK explanation: maybe

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Point A (4,-3) is reflected over the y- axis. What are<br> the coordinates of A'?
yan [13]

Answer:

A'(-4,-3)

Step-by-step explanation:

use formula of reflection over y axis

(x,y)=(-x,y)

A(4,-3)=A'(-4,-3)

5 0
2 years ago
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If (5x-3y)²=0, then x/y=?​
alexandr1967 [171]

Answer:

\frac{3}{5}

Step-by-step explanation:

Given

(5x - 3y)² = 0, then

5x - 3y = 0 ( add 3y to both sides )

5x = 3y (divide both sides by 5 )

x = \frac{3}{5} y ( divide both sides by y )

\frac{x}{y} = \frac{3}{5}

5 0
3 years ago
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Harlow can bicycle at a rate of 18 miles per hour.How many hours would it take him to bicycle a stretch mark of road that is 450
FromTheMoon [43]

Answer:

8100 Hours

Step-by-step explanation:

We all have heard of miles per hour, so just plug that formula into the question!

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Hope this helps!

6 0
3 years ago
The coordinate plane below represents a city. Points A through F are schools in the city.
Usimov [2.4K]
Part A. The technique on how to find the equation that only applies to point D and E, is to create a line or curve that only includes two of these points. In this case, I created a random parabola that isolates points C and F from the rest of the points. First, we have to find the equation of the parabola through its general forms:

(x - h)² = +/-4a(y-k)      or    (y - k)² = +/-4a(x - h)

For parabolas drawn like that in the picture, the general form is (x - h)² = +4a(y-k), where the vertex is (h,k) and a is the distance from the vertex to the focus. From the picture, the vertex is at (0,3). Then, we use point D(-2,4) to determine a:

(-2 - 0)² = +4a(4 - 3)
4a = 4

So, the equation of the parabola is:

x² = 4(y - 3)
x² = 4y - 12

Part B. Point D was already verified above. Now for point E(2,4)
x² = 4y - 12
2² ? 4(4) - 12
4 ? 4
4 = 4

Part C. For y < 7x − 4, ignore the equality symbol first and graph the line. Assign random values of x, then you get corresponding values of y. Plot them as shown in the second picture. The line is shown in red. Next, test the equation by choosing a random point. Let's choose the purple point at (4,3).

3 ? 7(4) − 4
3 ? 24
3 < 24

Thus, it applies to the purple point, and all the other areas to that area. The shaded region are all solutions of the inequality. So, Erica is only interested in points E, C and F. 

5 0
3 years ago
Please help with this
nataly862011 [7]

Answer:

AAS

Step-by-step explanation:

3 0
3 years ago
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