Answer:
The work is in the explanation.
Step-by-step explanation:
The sine addition identity is:
.
The sine difference identity is:
.
The cosine addition identity is:
.
The cosine difference identity is:
.
We need to find a way to put some or all of these together to get:
.
So I do notice on the right hand side the
and the
.
Let's start there then.
There is a plus sign in between them so let's add those together:

![=[\sin(a+b)]+[\sin(a-b)]](https://tex.z-dn.net/?f=%3D%5B%5Csin%28a%2Bb%29%5D%2B%5B%5Csin%28a-b%29%5D)
![=[\sin(a)\cos(b)+\cos(a)\sin(b)]+[\sin(a)\cos(b)-\cos(a)\sin(b)]](https://tex.z-dn.net/?f=%3D%5B%5Csin%28a%29%5Ccos%28b%29%2B%5Ccos%28a%29%5Csin%28b%29%5D%2B%5B%5Csin%28a%29%5Ccos%28b%29-%5Ccos%28a%29%5Csin%28b%29%5D)
There are two pairs of like terms. I will gather them together so you can see it more clearly:
![=[\sin(a)\cos(b)+\sin(a)\cos(b)]+[\cos(a)\sin(b)-\cos(a)\sin(b)]](https://tex.z-dn.net/?f=%3D%5B%5Csin%28a%29%5Ccos%28b%29%2B%5Csin%28a%29%5Ccos%28b%29%5D%2B%5B%5Ccos%28a%29%5Csin%28b%29-%5Ccos%28a%29%5Csin%28b%29%5D)


So this implies:

Divide both sides by 2:

By the symmetric property we can write:

Answer:
Ur answer is #1 = A number line from negative 10 to 10 is shown with numbers labeled at intervals of 2. An arrow is shown from point 0 to negative 2. Another arrow points from negative 2 to 8.
Step-by-step explanation:
The arrow from 0 to -2 represents the initial "-2" of the problem. <em>Adding </em>-10 would put an arrow of length 10 from that point to the left to -12. However, you are <em>subtracting </em>-10, so that arrow is reversed and goes from -2 to +8.
A cross section is the shape we get when cutting straight through an object. The cross section of this object is a triangle. It is like a view into the inside of something made by cutting through it.
Answer:
Sitting fee - 32$
Step-by-step explanation:
This is a system of equations(let x represent the sitting fee)
x+6y=50
x+11y=65
You want to isolate the x variable - x+6y-6y=50-6y ; x = 50-6y
Input this into the 2nd equation: 50-6y+11y=65 ; 50+5y=65
Subtract 50 from both sides. 5y=15 (Divided 5y on both sides) ; y=3
Now that y = 3 input this into any equation I choose the 1st one.
x+6(3) = 50 ; x + 18 = 50 (Subtract 18 on both sides to get x)
x = 32
Prove: 32 + 6(3) = 50 ; 32+18 = 50 ; 50 = 50 True