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erica [24]
2 years ago
11

10 1/4 divided by 2 1/2

Mathematics
2 answers:
gtnhenbr [62]2 years ago
6 0

Answer: 4.1

Step-by-step explanation:

Aleksandr [31]2 years ago
3 0

Answer:

4 1/10

hope this helps have a good day :)

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There is a pair of parallel sides in the following shape.<br> 9. 5. 3
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area of composite shapes is area of rectangle plus area of square what do I know I'm just in 8th grad

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Which set of rectangular coordinates describes the same location as the polar coordinates (4,pi)?
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\bf (\stackrel{r}{4}~,~\stackrel{\theta }{\pi })\qquad \begin{cases} x=&rcos(\theta )\\ &4cos(\pi )\\ &4(-1)\\ &-4\\ y= &rsin(\theta )\\ &4sin(\pi )\\ &4(0)\\ &0\\ \end{cases}\qquad \implies (\stackrel{x}{-4}~,~\stackrel{y}{0})

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One planet holds 14 Tomato seedlings. If you have 1,113 seedlings, how many containers do you need to hold all seedlings?
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Answer:

If your talking about the containers, then you would need 80

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Step-by-step explanation:

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3 years ago
Write an equation in slope-intercept form of the line that passes through (5,−1) and (4,3)
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7 0
3 years ago
A consumer organization inspecting new cars found that many had appearance defects (dents, scratches, paint chips, etc.). While
Murljashka [212]

Answer:

The expected number of appearance defects in a new car  = 0.64

standard deviation = 0.93(approximately)

Step-by-step explanation:

Given -

7% had exactly three, 11% exactly two, and 21% only one defect in cars.

Let X be no of defects in a car

P(X=3) = .07 , P(X=2) = .11 , P(X=3) = .21

P(X=0 ) = 1 - .07 - .11 - .21 = 0.61

The expected number of appearance defects in a new car =

E(X) = \nu = = \sum X P(X) =3\times 0.07 + 2\times0.11 + 3\times0.21 + 0\times0.61 = 0.64

\sigma^{2}  = variation of E(X) = \sum (X - \nu) ^{2}P(X) = (3 - 0.64) ^{2}\times0.07 + (2 - 0.64) ^{2}\times0.11 + (1 - 0.64) ^{2}\times0.21 + (0 - 0.64) ^{2}\times0.61

 = (2.36) ^{2}\times0.07 + (1.36) ^{2}\times0.11 + (.36) ^{2}\times0.21 + ( 0.64) ^{2}\times0.61 = 0.8704

standard deviation  =  \sqrt{\sigma^{2}} = \sqrt{0.8704^{2}} = 0.93(approximately)

4 0
3 years ago
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