Would this work? Hope it helps
Answer:
g(x)=−4x^2 and m(x)=4x^2
Step-by-step explanation:
A horizontal stretch or shrink happens when you multiply the parent function (in this case f(x) = x²) by a number. If this number is between 0 and 1, the graph will be stretched horizontally. If this number is greater than 1, the graph will be shrunk horizontally. If the number is between -1 and 0, the graph will be stretched horizontally and flipped; if the number is less than -1, the graph will be shrunk horizontally and flipped.
The graphs that are horizontally shrunk are steeper than the others. This is m(x)=4x^2 and g(x) = -4x^2.
complette the square to get vertex form or y=a(x-h)^2+k
(h,k) is vertex
1. group x terms, so for y=ax^2+bx+c, do y=(ax^2+bx)+c
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2, factor out the leading coefinet (constant in front of the x^2 term), basicallly factor out a
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3. take 1/2 of the linear coefient (number in
front of the x), and square it ,then add negative and positive of it
inside parnthases
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4. complete the squre and expand
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so
y=-1/4x^2+4x-19
group
y=(-1/4x^2+4x)-19
undistribute -1/4
y=-1/4(x^2-16x)-19
take 1/2 of -16 and squer it to get 64 then add neg and pos inside
y=-1/4(x^2-16x+64-64)-19
factorperfect square
y=-1/4((x-8)^2-64)-19
expand
y=-1/4(x-8)^2+16-19
y=-1/4(x-8)^2-3
vertex is (8,-3)
Answer:
#3. d = -10.25
Step-by-step explanation:
#3. d = -6.5 + -3.75
