Answer:
a_s=4.8\times 10^{-2}~m^2
Explanation:
Given:
cross-sectional area of the bone, a=4.8 \times 10^{-4} ~m^2
the factor of up-scaling the dimensions, s=10
Since we need to find the upscaled area having two degrees of the dimension therefore the scaling factor gets squared for the area being it in 2-dimensions.
The scaled-up area is:
a_s=a\times s^2
a_s=[4.8 \times 10^{-4}]\times 10^2
a_s=4.8\times 10^{-2}~m^2