if its diameter is 6, then its radius is half that or 3.
![\textit{volume of a cone}\\\\ V=\cfrac{\pi r^2 h }{3}~~ \begin{cases} r=radius\\ h=height\\[-0.5em] \hrulefill\\ r=3\\ h=4 \end{cases}\implies V=\cfrac{\pi (3)^2(4)}{3}\implies V=12\pi \\\\[-0.35em] ~\dotfill\\\\ \textit{surface area of a cone}\\\\ SA=\pi r\sqrt{r^2+h^2}+\pi r^2\qquad \implies \qquad SA=\pi (3)\sqrt{3^2+4^2}+\pi (3)^2 \\\\\\ 3\pi \sqrt{25}+9\pi \implies 3\pi (5)+9\pi \implies 15\pi +9\pi \implies 24\pi](https://tex.z-dn.net/?f=%5Ctextit%7Bvolume%20of%20a%20cone%7D%5C%5C%5C%5C%20V%3D%5Ccfrac%7B%5Cpi%20r%5E2%20h%20%7D%7B3%7D~~%20%5Cbegin%7Bcases%7D%20r%3Dradius%5C%5C%20h%3Dheight%5C%5C%5B-0.5em%5D%20%5Chrulefill%5C%5C%20r%3D3%5C%5C%20h%3D4%20%5Cend%7Bcases%7D%5Cimplies%20V%3D%5Ccfrac%7B%5Cpi%20%283%29%5E2%284%29%7D%7B3%7D%5Cimplies%20V%3D12%5Cpi%20%5C%5C%5C%5C%5B-0.35em%5D%20~%5Cdotfill%5C%5C%5C%5C%20%5Ctextit%7Bsurface%20area%20of%20a%20cone%7D%5C%5C%5C%5C%20SA%3D%5Cpi%20r%5Csqrt%7Br%5E2%2Bh%5E2%7D%2B%5Cpi%20r%5E2%5Cqquad%20%5Cimplies%20%5Cqquad%20SA%3D%5Cpi%20%283%29%5Csqrt%7B3%5E2%2B4%5E2%7D%2B%5Cpi%20%283%29%5E2%20%5C%5C%5C%5C%5C%5C%203%5Cpi%20%5Csqrt%7B25%7D%2B9%5Cpi%20%5Cimplies%203%5Cpi%20%285%29%2B9%5Cpi%20%5Cimplies%2015%5Cpi%20%2B9%5Cpi%20%5Cimplies%2024%5Cpi)
The coefficient of x in the equation of the given line, 3, is its slope. The slope of the perpendicular line is the negatve reciprocal of that, -1/3. You now have the slope and a point on the perpendicular line, so you can write its equation using the point-slope form:
y = m(x -x₁) +y₁
where m is the slope and (x₁, y₁) is the point.
An equation for your perpendicular line is
y = (-1/3)(x -(-1)) -3
y = (-1/3)x -10/3
The slope-intercept form of the equation of the perpendicular line is ...
y = (-1/3)x -10/3
Answer:
$1.04
Step-by-step explanation:
8% of 13 is 1.04
Answer:
4y + 5x + 13
Step-by-step explanation:
4y + 3(y + 1) + 2(x+5)
Distribute
4y + 3y + (3 x 1) + 2x + (2 x 5)
4y + 3y + 3 + 2x + 10
Combine like terms
4y + 5x + 13
Answer:
Your answer is in the picture.
Step-by-step explanation:
Visit the website if you want to factor polynomial.