The capital letter W is expressed as U+0057 in Unicode system
- The Unicode system is known as a type of coding system which contains worldwide character encoding standard that gives a code to every character and symbol in every language spoken in the world today.
- It is known as the encoding standard that is used in all languages, It makes sure that an individual can retrieve or combine data with the use of different languages altogether.
Conclusively, we can say that the The capital letter W is expressed as U+0057 in Unicode system
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<u>Answer:</u>
<em>using System;
</em>
<em>public class Program
</em>
<em>{
</em>
<em> public static void Main()
</em>
<em> {
</em>
<em> String input ;
</em>
<em> while(true)
</em>
<em> {
</em>
<em> input = Console.ReadLine();
</em>
<em> if(input.Equals(""quit""))
</em>
<em> break;
</em>
<em> Reverse_String(input);
</em>
<em> }
</em>
<em> return;
</em>
<em> }
</em>
<em>static void Reverse_String(string input_text)
</em>
<em>{
</em>
<em> char[] text = input_text.ToCharArray();
</em>
<em> Array.Reverse(text);
</em>
<em> Console.WriteLine(text);
</em>
<em>}
</em>
<u>Explanation:</u>
<em>In the above program a separate function is written to reverse the string.</em>
This method takes the string as an argument and place it in a array and then use the built-in function reverse and print the reversed string in the console.
<em>In the main(), the input is obtained from the console and it is passed to the reversestring().
</em>
The answer to ur question is D
Answer:
(a)Applications Time Stamp Events
(b)S=0.5(W-)+, where ≤W≤+8.
Explanation:
Some applications assume that clocks always advance, so they could timestamp events under this assumption.
In our case we have the wrong timed clock, say W and the hardware clock H which is supposed to advance at a perfect rate.
We proceed to construct a software clock such that after 8 seconds we can replace the wrong timed clock with the software clock in good conditions.
Let us denote the software clock with S.
Then, S=c(W-)+ where:
=The current Time(10:27:54) and;
c is to be found.
We already know that S=+4 when W= +8,
So:
S=c(W-)+
+4=c(+8-)+
4=8c
c=0.5
We obtain the formula
S=0.5(W-)+, where ≤W≤+8.
import java.util.Scanner;
public class U3_L6_Activity_Two{
public static void main(String[] args){
Scanner scan = new Scanner(System.in);
int x = scan.nextInt();
int y = scan.nextInt();
if(x>=4|| ((y < 5) && ((x+y) < 7))){
System.out.println("pass");
}
}
}
I'm pretty sure this is what you're looking for. Best of luck.