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2 years ago

Consider the rectangle with width 8 cm and length 20 cm, write a ratio of the width to length.

Mathematics

1 answer:

NISA [10]2 years ago

3 0

Step-by-step explanation:

A ratio is a relation between two numbers.

*A ratio determines how many times 20 contains/values 8.

A ratio representing the width to the length is:

8:20.

8 represents the width, 20 represents the length.

To simplify a ratio, you must divide each side by the same number.

Simplified ratios are:

4:10 (Divide by 2)

2:5 (Divide by 4)

1:2.5 (Divide by 8)

The ratio is detailing that the length is 2.5 times larger than the width.

Your answers are;

8:20

4:10

2:5

1:2.5

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jekas [21]

Answer:

Step-by-step explanation:

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3 years ago

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The cities Cleveland, Ohio; Erie, Pennsylvania; and Rochester, New York, in respective order, lie approximately in a straight li

Ann [662]

Answer:

Erie to Rochester is 145 miles

Step-by-step explanation:

If we designate the points of interest as C, E, and R, we are told that ...

CE + ER = CR . . . . . the various distances are segments of a straight line

For CE = 94 and CR = 239, we can fill in the given information and solve for ER.

94 + ER = 239

ER = 239 -94 . . . . . . subtract 94 from both sides of the equation

ER = 145

The distance from Erie to Rochester is 145 miles.

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3 years ago

A swimming pool has a diameter of 24 feet. What is the minimum amount of fabric needed to cover the pool if the cover must hang

Alika [10]

Answer:

531.167 ft²

Step-by-step explanation:

Given data

Dimension of pool

Diameter =24ft

Radius =12ft

If the cover must hang by 1ft around, then the diameter is 26ft

Radius =13ft

Area of cover = πr²

Substitute

Area = 3.142*13²

Area =3.143*169

Area =531.167 ft²

Hence the minimum area is 531.167 ft²

5 0

3 years ago

Zigmanuir [339]

Answer:

The weight of the water in the pool is approximately 60,000 lb·f

Step-by-step explanation:

The details of the swimming pool are;

The dimensions of the rectangular cross-section of the swimming pool = 10 feet × 20 feet

The depth of the pool = 5 feet

The density of the water in the pool = 60 pounds per cubic foot

From the question, we have;

The weight of the water in Pound force = W = The volume of water in the pool given in ft.³ × The density of water in the pool given in lb/ft.³ × Acceleration due to gravity, g

The volume of water in the pool = Cross-sectional area × Depth

∴ The volume of water in the pool = 10 ft. × 20 ft. × 5 ft. = 1,000 ft.³

Acceleration due to gravity, g ≈ 32.09 ft./s²

∴ W = 1,000 ft.³ × 60 lb/ft.³ × 32.09 ft./s² = 266,196.089 N

266,196.089 N ≈ 60,000 lb·f

The weight of the water in the pool ≈ 60,000 lb·f

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3 years ago

A manufacturer cuts squares from the corners of a rectangular plece of sheet metal that measures 2 inches by 7 inches (see Figur

Vladimir79 [104]

Answer:

The value of x that maximizes the volume enclosed by this box is 0.46 inches

The maximum volume is 3.02 cubic inches

Step-by-step explanation:

see the attached figure to better understand the problem

we know that

The volume of the open-topped box is equal to

$V=LWH$

where

$L=(7-2x)\ in\\W=(2-2x)\ in\\H=x\ in$

substitute

$V=(7-2x)(2-2x)x$

Convert to expanded form

$V=(7-2x)(2-2x)x\\V=(14-14x-4x+4x^{2})x\\V=14x-14x^2-4x^2+4x^{3}\\V=4x^{3}-18x^{2} +14x$

using a graphing tool

Graph the cubic equation

Remember that

The domain for x is the interval -----> (0,1)

Because

If x>1

then

the width is negative (W=2-2x)

The maximum is the point (0.46,3.02)

see the attached figure

therefore

The value of x that maximizes the volume enclosed by this box is 0.46 inches

The maximum volume is 3.02 cubic inches

8 0

3 years ago