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bogdanovich [222]
3 years ago
10

Pipe A can fill a tank in 40 minutes, while pipe B takes 60 minutes to fill the same tank.

Mathematics
1 answer:
ella [17]3 years ago
4 0

Answer:

24 minutes.

Step-by-step explanation:

This question shows up in a great many places in math or physics, so it is a pretty good question to learn how to do.

First you should note that answer will be under 40 minutes.

1/40 + 1/60 = 1/TimeTotal

The common denominator on the left is 120 minutes

3/40*3 + 2/60*2 = 1/timetotal

3/120 + 2/120      = 1/ timetotal

5/120 = 1/time total  Now to use to the key stop

What you do now is you always turn the left side over. You do the same thing to total time.

120/5 = total time

24 = total time

What this means is that if you let both pipes run for 24 minutes, they will fill the tank working together.

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PLEASE HELP ASAP!!! I NEED CORRECT ANSWERS ONLY PLEASE!!! I NEED TO FINISH THESE QUESTIONS BEFORE MIDNIGHT TONIGHT.
Lina20 [59]

Yo sup??

we can solve this question by applying trigonometric ratios

cos59=CB/CD

CD=CB/cos59

=7.8

Hope this helps.

7 0
3 years ago
Please simplify the following equation and show how:<br> (2x+2)^3
Natasha_Volkova [10]
<span> </span>

You can use (a+b)2 = a2+2ab+b2.
(2x - 3)2 = (2x)2 + 2(2x)(-3) + (-3)2 = 4x2 - 12x + 9

Or you can use FOIL.

(2x - 3)2 = (2x - 3)(2x - 3) = (2x)2 + (2x)(-3) + (-3)(2x) + (-3)2 = 4x2 - 12x + 9



hope I could be helpful

7 0
3 years ago
Read 2 more answers
Suppose that 35 people are divided in a random manner into two teams in such a way that one team contains 10 people and the othe
Effectus [21]

Answer:

0.5798 or 57.98%

Step-by-step explanation:

The total number of ways to form the two teams is the combination of choosing 10 people out of 35 (₃₅C₁₀). The number of possibilities that A and B are both on the 10-people team is given by the combination of choosing 8 people (since two are fixed) out of 33 (₃₃C₈).The number of possibilities that A and B are both on the 25-people team is given by the combination of choosing 10 people out of 33 (₃₃C₈).

Therefore, the probability that two particular people A and B will be on the same team is:

P = \frac{_{33}C_8+_{33}C_{10}}{_{35}C_{10}} \\\\P=\frac{\frac{33!}{(33-8)!8!}+\frac{33!}{(33-10)!10!} }{\frac{35!}{(35-10)!10!}} \\\\P=\frac{69}{119} = 0.5798

The probability is 0.5798 or 57.98%.

8 0
3 years ago
Anyone know how to do this
Anton [14]

let

(hypotenuse ) c = 10 in

(perpendicular) a = 8 in

(base) b =?

By using Pythagoras theorem

c^2= a^2+b^2

(10)^2 = (8)^2 +(b)^2

100 = 64 +(b)^2

100- 64 = (b)^2

36 = (b)^2

√36 = b

6 = b

hence b= 6 in

3 0
2 years ago
Write 235 using powers of 10
vaieri [72.5K]

Answer:

(10^2)*2, 10*3, 10/2

Step-by-step explanation:

Thats my best guess to your very vague question

8 0
3 years ago
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