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2 years ago

Explainn why to Conduct introduction to TPM training?

1 answer:

8 0

The TPM is a cryptographic module that enhances computer security and privacy. Protecting data through encryption and decryption, protecting authentication credentials, and proving which software is running on a system are basic functionalities associated with computer security.

Total productive maintenance (TPM) is a team and shop floor based initiative focused on optimizing the effectiveness of manufacturing equipment. TPM helps workers efficiently care for the equipment and machines they work with, which will reduce costs, including money and space tied up with spare parts inventory.

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Ice dams are most directly related to:

musickatia [10]

Answer:

(B) heated air in an uninsulated, unvented attic.

Explanation:

-Ice dams are formed by an interaction between snow cover, outside temperatures, and heat lost through the roof – more specifically, from heat loss through the poorly insulated ceiling of the house into the attic area and under the roof.

-Hot, humid air trapped in attics can also cause moisture to accumulate, resulting in mold or mildew.

7 0

3 years ago

You installed a new 40 gallon water heater with a 54,000 BTUh burner. The underground water temperature coming into the house is

allochka39001 [22]

Answer:

For most uses you'll want your water heated to 120 F(49 C) In this example you'd need a demand water heater that produces a temperature rise and it will take about 2 hours

7 0

3 years ago

While discussing VIN numbers, Technician A says that the first digit of the VIN identifies the country where the vehicle was man

ruslelena [56]

Usually the first digit of the vin id’s the country it was built. So technician A would be correct. That’s usually how it is. Hope this helps. Please let me know if this is incorrect

4 0

3 years ago

The water level in a tank z1, is 20 m above the ground. A hose is connected to the bottom of the tank, and the nozzle at the end

Alika [10]

Answer:

the maximum height h to which the the water steam could rise is 40.65m

Explanation:

Given;

$Z_{1}$ = 20m,

$P_{1gage}$ = 2atm ≈ 20265 N/m

Density of water ρ = 1000 kg/ $m^{2}$

Note: we take point 1 at the free surface of the water in the tank and point 2 at the top of the water trajectory. we also take reference level at the bottom of the tank.

fluid velocity at the free surface of tank is very low ( $V_{1}$ ≅ 0) and at the top of the water trajectory $V_{2}$ = 0

Step 1: Applying Bernoulli equation between poin 1 and point 2

$P_{1}$ /ρg + $V_{1} ^{2}$ /2g + $Z_{1}$ = $P_{2}$ /ρg + $V_{2} ^{2}$ /2g + $Z_{2}$

$P_{1}$ /ρg + $Z_{1}$ = $P_{atm}$ /ρg + $Z_{2}$

$Z_{2}$ = ( $P_{1}$ - $P_{atm}$ )/ρg + $Z_{1}$

Substituting values into $Z_{2}$ we have,

$Z_{2}$ = $\frac{2atm}{(1000 kg/m^{3} )(9.81 m/s^{2} )} (\frac{101325N/m^{2} }{1atm} )(\frac{1 kg.m/s^{2} }{1N} ) + 20 = 40.65 m$

6 0

3 years ago

A thick aluminum block initially at 26.5°C is subjected to constant heat flux of 4000 W/m2 by an electric resistance heater whos

Yanka [14]

Given Information:

Initial temperature of aluminum block = 26.5°C

Heat flux = 4000 w/m²

Time = 2112 seconds

Time = 30 minutes = 30*60 = 1800 seconds

Required Information:

Rise in surface temperature = ?

Answer:

Rise in surface temperature = 8.6 °C after 2112 seconds

Rise in surface temperature = 8 °C after 30 minutes

Explanation:

The surface temperature of the aluminum block is given by

$T_{surface} = T_{initial} + \frac{q}{k} \sqrt{\frac{4\alpha t}{\pi} }$

Where q is the heat flux supplied to aluminum block, k is the conductivity of pure aluminum and α is the diffusivity of pure aluminum.

After t = 2112 sec:

$T_{surface} = 26.5 + \frac{4000}{237} \sqrt{\frac{4(9.71\times 10^{-5}) (2112)}{\pi} }\\\\T_{surface} = 26.5 + \frac{4000}{237} (0.51098)\\\\T_{surface} = 26.5 + 8.6\\\\T_{surface} = 35.1\\\\$

The rise in the surface temperature is

Rise = 35.1 - 26.5 = 8.6 °C

Therefore, the surface temperature of the block will rise by 8.6 °C after 2112 seconds.

After t = 30 mins:

$T_{surface} = 26.5 + \frac{4000}{237} \sqrt{\frac{4(9.71\times 10^{-5}) (1800)}{\pi} }\\\\T_{surface} = 26.5 + \frac{4000}{237} (0.4717)\\\\T_{surface} = 26.5 + 7.96\\\\T_{surface} = 34.5\\\\$

The rise in the surface temperature is

Rise = 34.5 - 26.5 = 8 °C

Therefore, the surface temperature of the block will rise by 8 °C after 30 minutes.

5 0

3 years ago