Answer:
See the attachment
Verification shown in explanation
Explanation:
wc= 1/(RC)
The value of R and C shown in the attachment can be calculated as follows:
R=100 ohms
1000= 1/(100×C)
C= 10 microfarads
Gain= R/√(R²+Xc²)
at f=500, wc= 3142.59 rad/s
Xc= 1/(2πfC)
Xc=31.83
Gain= 100/√(100²+31.83²)
Gain= 0.953
at fc= 100, wc= 628.32 rad/s
Xc= 159.15
gain= 100/√(100²+ 159.15²)
gain= 0.532
As see form calculations that gain at low frequencies is smaller and gain at very high frequencies is near to 1. This means that at high frequencies Vin≈ Vout
Hence this filter allows high frequencies to pass but blocks low frequencies by lowering the gai
Answer:
#Selling vehicles
import locale
locale.setlocale( locale.LC_ALL, 'en_CA.UTF-8' )
#Declaration of variables
total_pay=0
total_sales=0
#Selling details
for i in range(0,2):
#Ask the type of sell
type=input("Enter the type of the car you sold(used/new)? ")
#Check error
while(type.upper()!="USED" and type.upper()!="NEW"):
print('ERROR!!!Should be used or new!!Please Re-enter')
type=input("Enter the type of the car you sold(used/new)? ")
#Input price of the car
price=float(input("Enter the price of the car: "))
#Calculations
if(type.upper()=="NEW"):
total_pay+=1500
else:
total_pay+=price*.05
total_sales+=price
#Display results
print('Total Pay of the sale person = ',locale.currency(total_pay))
print('Total Sales = ',locale.currency(total_sales))
Answer:
-2/√3 atan ((2t + 1)/√3) + C
Explanation:
∫ (t − 1) / (1 − t³) dt
Factor the difference of cubes:
∫ (t − 1) / ((1 − t)(1 + t + t²)) dt
Divide:
∫ -1 / (1 + t + t²) dt
-∫ 1 / (t² + t + 1) dt
Complete the square:
-∫ 1 / (t² + t + ¼ + ¾) dt
-∫ 4 / (4t² + 4t + 1 + 3) dt
-∫ 4 / ((2t + 1)² + 3) dt
If u = 2t + 1, du = 2 dt:
-∫ 2 / (u² + 3) du
Use an integral table, or use trigonometric substitution:
-2 (1/√3) atan (u/√3) + C
-2/√3 atan (u/√3) + C
Substitute back:
-2/√3 atan ((2t + 1)/√3) + C
Answer: Extension is Final length - initial length. This implies : 31.6-31 =0.6. Therefore the extension is 0.6
Explanation:
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