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mario62 [17]
2 years ago
9

Jim's speedboat can travel 24 miles upstream against a 4 mph current. In the same amount of time it travels 26 miles

Mathematics
1 answer:
8_murik_8 [283]2 years ago
8 0

Answer:

speed of the boat = 100 mph

Step-by-step explanation:

Let x = speed of the boat

upstream speed = x - 4

downstream speed = x + 4

time = 24/(x - 4) = 26/(x + 4)

Cross multiply:

24(x + 4) = 26(x - 4)

24x + 96 = 26x - 104

104 + 96 = 26x - 24x

200 = 2x

x = 100 mph

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PIT_PIT [208]

Answer:

6.82 cm

Step-by-step explanation:

1000=V=pi*r^2*h. 1000=pi*r^3, r=6.82 cm

6 0
3 years ago
Help don’t understand
marusya05 [52]

Answer:

f(-14) = -6

f(-4) = 6

f(12) = 6

f(0) = -3

negative

Step-by-step explanation:

f(-14) = -6

This is because when x is -14, y is -6, as seen in the graph

f(-4) = 6

This is because when x is -4, y is 6, as seen in the graph

f(12) = 6

This is because when x is 12, y is 6, as seen in the graph

f(0) = -3

This is because when x is 0, y is -3, as seen in the graph

is f(4) positive or negative?
negative

This is because when x is 4, y is -6, as seen in the graph

6 0
2 years ago
PLEASE HELP!!
Mars2501 [29]

Answer:

51

Step-by-step explanation:

6 0
3 years ago
For each given p, let ???? have a binomial distribution with parameters p and ????. Suppose that ???? is itself binomially distr
pshichka [43]

Answer:

See the proof below.

Step-by-step explanation:

Assuming this complete question: "For each given p, let Z have a binomial distribution with parameters p and N. Suppose that N is itself binomially distributed with parameters q and M. Formulate Z as a random sum and show that Z has a binomial distribution with parameters pq and M."

Solution to the problem

For this case we can assume that we have N independent variables X_i with the following distribution:

X_i Bin (1,p) = Be(p) bernoulli on this case with probability of success p, and all the N variables are independent distributed. We can define the random variable Z like this:

Z = \sum_{i=1}^N X_i

From the info given we know that N \sim Bin (M,q)

We need to proof that Z \sim Bin (M, pq) by the definition of binomial random variable then we need to show that:

E(Z) = Mpq

Var (Z) = Mpq(1-pq)

The deduction is based on the definition of independent random variables, we can do this:

E(Z) = E(N) E(X) = Mq (p)= Mpq

And for the variance of Z we can do this:

Var(Z)_ = E(N) Var(X) + Var (N) [E(X)]^2

Var(Z) =Mpq [p(1-p)] + Mq(1-q) p^2

And if we take common factor Mpq we got:

Var(Z) =Mpq [(1-p) + (1-q)p]= Mpq[1-p +p-pq]= Mpq[1-pq]

And as we can see then we can conclude that   Z \sim Bin (M, pq)

8 0
3 years ago
When a bactericide is added to a nutrient broth in which bacteria are​ growing, the bacteria population continues to grow for a​
baherus [9]

Answer:

a)  1296 bacteria per hour

b) 0 bacteria per hour

c) -1296 bacteria per hour

Step-by-step explanation:

We are given the following information in the question:

The size of the population at time t​ is given by:

b(t) = 9^6 + 6^4t-6^3t^2

We differentiate the given function.

Thus, the growth rate is given by:

\displaystyle\frac{db(t)}{dt} = \frac{d}{dt}(9^6 + 6^4t-6^3t^2)\\\\= 6^4-2(6^3)t

a) Growth rates at t = 0 hours

\displaystyle\frac{db(t)}{dt} \bigg|_{t=0}= 6^4-2(6^3)(0) = 1296\text{ bacteria per hour}

b) Growth rates at t = 3 hours

\displaystyle\frac{db(t)}{dt} \bigg|_{t=3}= 6^4-2(6^3)(3) = 0\text{ bacteria per hour}

c) Growth rates at t = 6 hours

\displaystyle\frac{db(t)}{dt} \bigg|_{t=6}= 6^4-2(6^3)(6) = -1296\text{ bacteria per hour}

3 0
4 years ago
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