Answer:
1. f
2. a
3. b
4. e
5. c
6. d
1. I figured out how to order them by using the distance formula to calculate how far each point was, from the other.
2. (1, -10) and (1, -11)
3. (1, -10) and (1, 11)
Step-by-step explanation:
<u>Using Letter A, as example:</u>
To calculate the distance between the points, you use the formula:
d = 6
Just do the same thing (plug in the numbers into the formula), and you should be able to get the correct answers.
If Eric plays piano, then David will sing.
Answer: 12 hours and 24 Minutes
Step-by-step explanation:
7*60 = 420
810/420 = 1.9285
93- 100 = 53-60
subtract 40 from 93.
1.53*8 = 12.24
Answer: 12 hours and 24 Minutes
9514 1404 393
Answer:
∠Q = 89°
∠R = 123°
∠S = 91°
Step-by-step explanation:
It seems easiest to start by finding the measures of each of the arcs. The measure of an arc is double the measure of the inscribed angle it subtends.
arc QRS = 2·∠P = 114°
So, ...
arc QR = arc QRS - arc RS = 114° -41° = 73°
The total of the arcs around the circle is 360°, so ...
arc PQ = 360° -arc PS -arc QRS
arc PQ = 360° -137° -114° = 109°
__
∠Q = (1/2)(arc RS + arc PS) = (1/2)(41° +137°)
∠Q = 89°
__
∠R = (1/2)(arc PS +arc PQ) = (1/2)(137° +109°)
∠R = 123°
__
∠S = (1/2)(arc PQ +arc QR) = (1/2)(109° +73°)
∠S = 91°
This is quite a complex problem. I wrote out a really nice solution but I can't work out how to put it on the website as the app is very poorly made. Still, I'll just have to type it all in...
Okay so you need to use a technique called logarithmic differentiation. It seems quite unnatural to start with but the result is very impressive.
Let y = (x+8)^(3x)
Take the natural log of both sides:
ln(y) = ln((x+8)^(3x))
By laws of logarithms, this can be rearranged:
ln(y) = 3xln(x+8)
Next, differentiate both sides. By implicit differentiation:
d/dx(ln(y)) = 1/y dy/dx
The right hand side is harder to differentiate. Using the substitution u = 3x and v = ln(x+8):
d/dx(3xln(x+8)) = d/dx(uv)
du/dx = 3
Finding dv/dx is harder, and involves the chain rule. Let a = x+ 8:
v = ln(a)
da/dx = 1
dv/da = 1/a
By chain rule:
dv/dx = dv/da * da/dx = 1/a = 1/(x+8)
Finally, use the product rule:
d/dx(uv) = u * dv/dx + v * du/dx = 3x/(x+8) + 3ln(x+8)
This overall produces the equation:
1/y * dy/dx = 3x/(x+8) + 3ln(x+8)
We want to solve for dy/dx, achievable by multiplying both sides by y:
dy/dx = y(3x/(x+8) + 3ln(x+8))
Since we know y = (x+8)^(3x):
dy/dx = ((x+8)^(3x))(3x/(x+8) + 3ln(x+8))
Neatening this up a bit, we factorise out 3/(x+8):
dy/dx = (3(x+8)^(3x-1))(x + (x+8)ln(x+8))
Well wasn't that a marathon? It's a nightmare typing that in, I hope you can follow all the steps.
I hope this helped you :)
