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strojnjashka [21]
3 years ago
13

The proportion of students in a psychology experiment who could remember an eight-digit number correctly for t minutes was 0.9 −

0.4 ln(t) (for t > 1). Find the proportion that remembered the number for 7 minutes. (Round your answer to one decimal place.)
Mathematics
1 answer:
kaheart [24]3 years ago
8 0

Answer:

The proportion would be 0.1

Step-by-step explanation:

Given, the function that shows the proportion of students in a psychology experiment who could remember an eight-digit number correctly for t minutes,

f(t) = 0.9 - 0.4\ln(t)

If t = 7 minutes,

f(7) = 0.9 - 0.4\ln(7)=0.9 - 0.77836=0.12164\approx 0.1

Hence, the proportion that remembered the number for 7 minutes is 0.1 ( approx )

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Answer: it’s b

Step-by-step explanation:

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One angle of an isosceles triangle measures 96 degrees. Which other angles could be in that isosceles triangle?
Fofino [41]
One angle of an isosceles triangle measures 96 degrees. Which other angles could be in that isosceles triangle?

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3 years ago
148=3x+3+4x+1 solve
Andreas93 [3]

Answer: 20.57142857

Step-by-step explanation:

148 = 3x + 3 + 4x + 1

Step one: combine like terms

148 = 7x + 4

Step 2: Subtract the 4 over to 148

144 = 7x

Step 3: Divide 7 on both sides

20.57142857 = x

6 0
3 years ago
A candidate for a US Representative seat from Indiana hires a polling firm to gauge her percentage of support among voters in he
mojhsa [17]

Answer:

(A) The minimum sample size required achieve the margin of error of 0.04 is 601.

(B) The minimum sample size required achieve a margin of error of 0.02 is 2401.

Step-by-step explanation:

Let us assume that the percentage of support for the candidate, among voters in her district, is 50%.

(A)

The margin of error, <em>MOE</em> = 0.04.

The formula for margin of error is:

MOE=z_{\alpha /2}\sqrt{\frac{p(1-p)}{n}}

The critical value of <em>z</em> for 95% confidence interval is: z_{\alpha/2}=1.96

Compute the minimum sample size required as follows:

MOE=z_{\alpha /2}\sqrt{\frac{p(1-p)}{n}}\\0.04=1.96\times \sqrt{\frac{0.50(1-0.50)}{n}}\\(\frac{0.04}{1.96})^{2} =\frac{0.50(1-0.50)}{n}\\n=600.25\approx 601

Thus, the minimum sample size required achieve the margin of error of 0.04 is 601.

(B)

The margin of error, <em>MOE</em> = 0.02.

The formula for margin of error is:

MOE=z_{\alpha /2}\sqrt{\frac{p(1-p)}{n}}

The critical value of <em>z</em> for 95% confidence interval is: z_{\alpha/2}=1.96

Compute the minimum sample size required as follows:

MOE=z_{\alpha /2}\sqrt{\frac{p(1-p)}{n}}\\0.02=1.96\times \sqrt{\frac{0.50(1-0.50)}{n}}\\(\frac{0.02}{1.96})^{2} =\frac{0.50(1-0.50)}{n}\\n=2401.00\approx 2401

Thus, the minimum sample size required achieve a margin of error of 0.02 is 2401.

8 0
3 years ago
A small ball floats on the surface of the water in a wave pool. As a wave moves past the ball, the ball's
stiks02 [169]

Answer:

The correct option is;

d(t) = 6·cos(π/3·t) + 28

Step-by-step explanation:

The general form of a cosine function is given as follows;

y = A·cos(B·x - C) + D

Where;

A = The amplitude = The distance from the peak to the midline = 1/2×(Maximum - minimum)

The amplitude = 1/2 × (34 - 22) = 6 inches

B = 2·π/P = 2·π/6 = π/3

P = The period = 6 seconds

C/B = The phase shift

D = The midline = Minimum  + Amplitude = 22 + 6 = 28 inches

x = The independent variable

Therefore, to model the function of the wave can be given as follows;

d(t) = 6·cos(π/3·t) + 28

6 0
3 years ago
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