Answer:
Step-by-step explanation:
For each component, there are only two possible outcomes. Either it fails, or it does not. The components are independent. We want to know how many outcomes until r failures. The expected value is given by
In which r is the number of failures we want and p is the probability of a failure.
In this problem, we have that:
r = 1 because we want the first failed unit.
![p = 0.4[\tex]So[tex]E = \frac{r}{p} = \frac{1}{0.4} = 2.5](https://tex.z-dn.net/?f=p%20%3D%200.4%5B%5Ctex%5D%3C%2Fp%3E%3Cp%3ESo%3C%2Fp%3E%3Cp%3E%5Btex%5DE%20%3D%20%5Cfrac%7Br%7D%7Bp%7D%20%3D%20%5Cfrac%7B1%7D%7B0.4%7D%20%3D%202.5)
The expected number of systems inspected until the first failed unit is 2.5
Answer:
the mean weight is 22 tonnes
Step-by-step explanation:
mean=total sum/number of numbers you added
in this case the question already gave you the total so just divide right away
mean weight= 330/15 = 22 tonnes
Answer:
1. X= 25.9 meters
2.X= 21.3 meters
Step-by-step explanation:
1. Tan 50°= X/21
2. Tan 12°= X/100
Answer is 74. Greater than 70 less than 80 so some where in the 70s. It has 4 ones so it would be 74.
K can be 10,11,14,25
Work
(2x+4)(X+3)
(2x+3(X+4)
(2x+6)(X+2)
(2x+2)(X+6)
(2x+1)(X+12)
(2x+12)(X+1)
