Answer:
1. The sides are: 38.5, 39.5, 40.5 and 41.5
2. Presently, Inzo is 15 years old and Miz is 10 years old
3. ![Distance = 3682km](https://tex.z-dn.net/?f=Distance%20%3D%203682km)
4. Possible pairs are: (12, 14), (16, 18) and (20, 24)
5. ![L < 38m](https://tex.z-dn.net/?f=L%20%3C%2038m)
Step-by-step explanation:
The question has lots of missing details. See the comment section for complete question
Solving (a):
Given
Shape: Quadrilateral
Sides: Consecutive
![Perimeter = 160](https://tex.z-dn.net/?f=Perimeter%20%3D%20160)
Let one of the sides be x. The other sides will be x + 1, x + 2 and x + 3.
So, the perimeter is:
![Perimeter = x + x + 1 + x + 2 + x + 3](https://tex.z-dn.net/?f=Perimeter%20%3D%20x%20%2B%20x%20%2B%201%20%2B%20x%20%2B%202%20%2B%20x%20%2B%203)
This gives:
![160 = x + x + 1 + x + 2 + x + 3](https://tex.z-dn.net/?f=160%20%3D%20x%20%2B%20x%20%2B%201%20%2B%20x%20%2B%202%20%2B%20x%20%2B%203)
Collect Like Terms
![160 -1-2-3= x+x+x+x](https://tex.z-dn.net/?f=160%20-1-2-3%3D%20x%2Bx%2Bx%2Bx)
![154= 4x](https://tex.z-dn.net/?f=154%3D%204x)
Divide both sides by 4
![38.5 = x](https://tex.z-dn.net/?f=38.5%20%3D%20x)
![x =38.5](https://tex.z-dn.net/?f=x%20%3D38.5)
<em>So, the sides are: 38.5, 39.5, 40.5 and 41.5</em>
<em></em>
Solving (b):
Given
Presently: ![Inzo = 10 + Miz](https://tex.z-dn.net/?f=Inzo%20%3D%2010%20%2B%20Miz)
Five years ago:
--- (Missing from the question)
Required: Determine their present ages
Substitute
for Inzo in the second equation
![Miz - 5 = \frac{1}{3} * (10 + Miz - 5)](https://tex.z-dn.net/?f=Miz%20-%205%20%3D%20%5Cfrac%7B1%7D%7B3%7D%20%2A%20%2810%20%2B%20Miz%20-%205%29)
![Miz - 5 = \frac{1}{3} * (Miz + 5)](https://tex.z-dn.net/?f=Miz%20-%205%20%3D%20%5Cfrac%7B1%7D%7B3%7D%20%2A%20%28Miz%20%2B%205%29)
Multiply both sides by 3
![3Miz - 15 = Miz + 5](https://tex.z-dn.net/?f=3Miz%20-%2015%20%3D%20Miz%20%2B%205)
Collect Like Terms
![3Miz -Miz = 15 + 5](https://tex.z-dn.net/?f=3Miz%20-Miz%20%3D%2015%20%20%2B%205)
![2Miz= 20](https://tex.z-dn.net/?f=2Miz%3D%2020)
Divide both sides by 2
![Miz = 10](https://tex.z-dn.net/?f=Miz%20%3D%2010)
Substitute 10 for Miz in ![Inzo = 10 + Miz](https://tex.z-dn.net/?f=Inzo%20%3D%2010%20%2B%20Miz)
![Inzo = 10 + 5](https://tex.z-dn.net/?f=Inzo%20%3D%2010%20%2B%205)
![Inzo = 15](https://tex.z-dn.net/?f=Inzo%20%3D%2015)
<em>So presently, Inzo is 15 years old and Miz is 10 years old</em>
Solving (3):
Given
Express Train:
![Speed = 100kph](https://tex.z-dn.net/?f=Speed%20%3D%20100kph)
![Time = t](https://tex.z-dn.net/?f=Time%20%3D%20t)
Local Train:
![Speed = 45kph](https://tex.z-dn.net/?f=Speed%20%3D%2045kph)
![Time = t + 45](https://tex.z-dn.net/?f=Time%20%3D%20t%20%2B%2045)
Required: Determine the distance between A and B
Distance is calculated as:
![Distance = Speed * Time](https://tex.z-dn.net/?f=Distance%20%3D%20Speed%20%2A%20Time)
For the express train:
![Distance = 100 * t](https://tex.z-dn.net/?f=Distance%20%3D%20100%20%2A%20t)
For the local train
![Distance = 45 * (45 + t)](https://tex.z-dn.net/?f=Distance%20%3D%2045%20%2A%20%2845%20%2B%20t%29)
Distance between both stations are equal; So,
![100 * t = 45 * (45 + t)](https://tex.z-dn.net/?f=100%20%2A%20t%20%3D%2045%20%2A%20%2845%20%2B%20t%29)
![100 t = 2025 + 45t](https://tex.z-dn.net/?f=100%20t%20%3D%202025%20%2B%2045t)
Collect Like Terms
![100 t -45t= 2025](https://tex.z-dn.net/?f=100%20t%20-45t%3D%202025)
![55t= 2025](https://tex.z-dn.net/?f=55t%3D%202025)
Divide by 55
![t = 36.82](https://tex.z-dn.net/?f=t%20%3D%2036.82)
Substitute 36.82 for t in ![Distance = 100 * t](https://tex.z-dn.net/?f=Distance%20%3D%20100%20%2A%20t)
![Distance = 100 * 36.82](https://tex.z-dn.net/?f=Distance%20%3D%20100%20%2A%2036.82)
![Distance = 3682km](https://tex.z-dn.net/?f=Distance%20%3D%203682km)
Solving (4):
Let the even numbers be: n and n + 2.
Sum greater than 24: ![n + n + 2 > 24](https://tex.z-dn.net/?f=n%20%2B%20n%20%2B%202%20%3E%2024)
Sum less than 60: ![n + n + 2 < 60](https://tex.z-dn.net/?f=n%20%2B%20n%20%2B%202%20%3C%2060)
So, we have:
![n + n + 2 > 24](https://tex.z-dn.net/?f=n%20%2B%20n%20%2B%202%20%3E%2024)
![2n + 2 > 24](https://tex.z-dn.net/?f=2n%20%2B%202%20%3E%2024)
Collect Like Terms
![2n > 24-2](https://tex.z-dn.net/?f=2n%20%3E%2024-2)
![2n > 22](https://tex.z-dn.net/?f=2n%20%3E%2022)
![n > 11](https://tex.z-dn.net/?f=n%20%3E%2011)
![n + n + 2 < 60](https://tex.z-dn.net/?f=n%20%2B%20n%20%2B%202%20%3C%2060)
![2n + 2< 60](https://tex.z-dn.net/?f=2n%20%2B%202%3C%2060)
Collect Like Terms
![2n < 60-2](https://tex.z-dn.net/?f=2n%20%3C%2060-2)
![2n < 58](https://tex.z-dn.net/?f=2n%20%3C%2058)
Divide by 2
![n](https://tex.z-dn.net/?f=n%3C29)
So, we have:
and ![n < 29](https://tex.z-dn.net/?f=n%20%3C%2029)
So, possible pairs are: (12, 14), (16, 18) and (20, 24)
Solving (5):
Given
![Perimeter < 152m](https://tex.z-dn.net/?f=Perimeter%20%3C%20152m)
Required: Find the possible lengths
Let the length be L.
Perimeter is calculated as:
![Perimeter =4 * L](https://tex.z-dn.net/?f=Perimeter%20%3D4%20%2A%20L)
![Perimeter =4 L](https://tex.z-dn.net/?f=Perimeter%20%3D4%20%20L)
So, we have:
![4L < 152m](https://tex.z-dn.net/?f=4L%20%3C%20152m)
Divide through by 4
![L < 38m](https://tex.z-dn.net/?f=L%20%3C%2038m)
Hence, length is less than 38m (e.g. 37m)