Answer:
The amounts of money each has are:
Joe = $92
Charlie = $29
Leila = $23
Step-by-step explanation:
To solve this, we will convert the statements into an equation, and use that to solve for the unknowns, as follows:
total amount = $144
Let Leila's share be S
Joe's share = 4 times Leila's = 4S
Charlie's share = $6 + Leila's share = 6 + S
Joe's share + Charlie's Share + Leila's Share = $144
4S + (6 + S) + S = 144
4S + 6 + S + S = 144
4S + 2S + 6 = 144
6S + 6 = 144
6S = 144 - 6 = 138
S = 138 ÷ 6 = $23
Therefore Leila's share 'S' = $23
Joe share= 4S = 4 × 23 = $92
Charlie's share = 6 + 23 = $29
:) Hope this helps you to your question
Answer:
The table is show clearly in the figure attached.
P(boy if favourite activity is swimming) = 8/17 = 0.47
P(girl if favourite activity is sport) = 7/27 = 0.26
P(girl if favourite activity is reading) = 4/6 = 0.67
P(boy if favourite activity is sport) = 20/27 = 0.74
P(favourite activity is swimming if a girl) = 9/20 = 0.45
P(favourite activity is reading if a boy) = 2/30 = 0.07
P(favourite activity is swimming if a boy) = 8/30 = 0.27
P(favourite activity is reading if a girl) = 4/20 = 0.2
Plotting the points could help you notice that they lie along a parabola. In particular, you can see that
is always 4 more than
.
So, the relation is
![y=x^2+4](https://tex.z-dn.net/?f=y%3Dx%5E2%2B4)
The frequency count that should be recorded for the soup category is 6.
<h3>What does subraction mean?</h3>
Subtraction is the process of taking one number away from another number. The sign used to represent subtraction is -.
<h3>What is the frequency count for the soup category?</h3>
The frequency count on the table should be equal to the number of students. Thus, in order to determine the frequency count for the soup category, subtract 22 from the total frequency count.
The frequency count for the soup category = 22 - (5 + 8 + 2 + 1 ) = 6
To learn more about subtraction, please check: brainly.com/question/915789