Question

A spinner is divided into two equal parts, one red and one blue. The set of possible outcomes when the spinner is spun twice is S = {RR, RB, BR, BB}. Let X represent the number of times blue occurs. Which of the following is the probability distribution, PX(x)? A 2-column table has 3 rows. The first column is labeled x with entries 0, 1, 2. The second column is labeled P x (x) with entries 0. 25, 0. 5, 0. 25. A 2-column table has 3 rows. The first column is labeled x with entries 0, 1, 2. The second column is labeled P x (x) with entries 0. 33, 0. 33, 0. 33. A 2-column table has 3 rows. The first column is labeled x with entries 0, 1, 2. The second column is labeled P x (x) with entries 0. 5, 0. 5, 0. A 2-column table has 3 rows. The first column is labeled x with entries 0, 1, 2. The second column is labeled P x (x) with entries 0, 0. 5, 0. 5.

Answer 1

A 2-column table that has 3 rows. The first column is labeled x with entries 0, 1, 2. The second column is labeled P x (x) with entries 0. 25, 0. 5, 0. 25.

What is Probability?

The probability helps us to know the chances of an event occurring.

$\rm{Probability=\dfrac{Desired\ Outcomes}{Total\ Number\ of\ outcomes\ possible}$

We know about the probability, therefore, let's find the probability of each of the cases.

When the number of success of the spinner landing on blue is none, therefore, the spinner does not land on the blue color at all.

$\rm{Probability=\dfrac{Desired\ Outcomes}{Total\ Number\ of\ outcomes\ possible}$

Now, as it is given that there is only one case when the spinner does not land on the blue side(RR) in the set, S = {RR, RB, BR, BB}. therefore,

$\rm{Probability(X=0)=\dfrac{1}{4} = 0.25$

When the number of success of the spinner landing on blue is just once, therefore, the spinner does land on the blue color only once out of the two spin.

$\rm{Probability=\dfrac{Desired\ Outcomes}{Total\ Number\ of\ outcomes\ possible}$

Now, as it is given that there are two cases when the spinner does land on the blue side(RB, BR) in the set, S = {RR, RB, BR, BB}. therefore,

$\rm{Probability(X=1)=\dfrac{2}{4} = 0.25$

When the number of success of the spinner landing on blue is twice, therefore, the spinner does land on the blue color both the times the spinner is spun.

$\rm{Probability=\dfrac{Desired\ Outcomes}{Total\ Number\ of\ outcomes\ possible}$

Now, as it is given that there is only one case when the spinner does land on the blue side twice(BB) in the set, S = {RR, RB, BR, BB}. therefore,

$\rm{Probability=\dfrac{1}{4} = 0.25$

Now, if we draw the table of the data and the probability we will get the following table,

x             P(X)

0           0.25

1            0.50

2           0.25

Hence, the table that is correct is table A, which is  A 2-column table that has 3 rows. The first column is labeled x with entries 0, 1, 2. The second column is labeled P x (x) with entries 0. 25, 0. 5, 0. 25.

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