What is the measure of angle B in the triangle?

Line L passes through the point (-1, 1) and is PARALLEL to the line shown here. An equation of line L is

Pachacha [2.7K]

The problem cannot be fully solved because you did provide the line on which the line is parallel/ but i can give you the steps on how to solve it. first solve the slope of the parallel line by
m = ( y2 - y1 ) / ( x2 - x1 )
then the slope of that line is equal to slope of line passing pooint ( -1 , 1)
then solve the y intercept of the line using
y = mx + b
where b is the y intercept
then you will have the equation of the line

5 0

3 years ago

Read 2 more answers

Plzzzzzzzzzzzzzzzzzzzzz answer!!!!!!!!!!!!!

GrogVix [38]

Answer:

This is quadratic trinomial

Step-by-step explanation:

It has x^2 (square) and consists of 3 parts

7 0

3 years ago

How many times can 4 go into 69

Black_prince [1.1K]

About 17 times. Just do 69/4

5 0

3 years ago

Read 2 more answers

Rich also has £400 pounds invest 3% compound interest . How many years does he need to invest the money to get at least £475

zepelin [54]

Answer: 6 years

Step-by-step explanation:

Formula to calculate compound amount: $A=P(1+r)^t$ , where P= Principal , r=rate of interest, t= time

Given: P = £400, r = 3% = 0.03 , A= 475

Required equation: $400(1+0.03)^t\geq475$

$400(1.03)^t\geq475\\\\\Rightarrow\ (1.03)^t\geq\dfrac{475}{400}\\\\\Rightarrow\ (1.03)^t\geq1.1875$

Taking log on both sides , we get

$t \log 1.03\geq\log1.1875\\\\\Rightarrow\ t(0.0128372)\geq(0.0746336)\\\\\Rightarrow\ t\geq\dfrac{0.0746336}{0.0128372}=5.81385\approx6$

Hence, he needs to invest the money for 6 years to get atleast £475.

7 0

2 years ago

Easy Sample Ap graphing 50pts! (Easy points!!) (ASAP) (URGENT) (Please check my other questions) Please

snow_lady [41]

Answer:

a) See attachment 1.

b) t² and D

c) See attachment 2.

d) g = 9.8 m/s² (1 d.p.)

Step-by-step explanation:

See attachment 1. The line of best fit is shown in red.

The quantities the student should graph in order to produce a <u>linear relationship</u> between the two quantities are t² and D.

Make a table of values of t² and D:

$\begin{array}{|l|l|l|l|l|l|}\cline{1-6} \rm t^2& 0.0196& 0.1024& 0.2116 & 0.3481& 0.3969\\\cline{1-6} \rm D & 0.10 & 0.50& 1.00 & 1.70 & 2.00\\\cline{1-6}\end{array}$

<u>Plot</u> a graph of D against t² and draw a line of best fit (see attachment 2).

From inspection of the graph, the line of best fit passes through the origin (0, 0) and (0.1024, 5.0). Therefore, use these two points to find the slope of the line:

$\textsf{slope}\:(m)=\dfrac{y_2-y_1}{x_2-x_1}=\dfrac{0.5-0}{0.1024-0}=4.8828125...\:\rm m/s^2$

Therefore:

$\rm \implies \dfrac{1}{2}g=4.8828125...\:\rm m/s^2$

$\rm \implies g=2 \cdot 4.8828125...\:\rm m/s^2$

$\rm \implies g=9.8\:\rm m/s^2\:(1\:d.p.)$

5 0

1 year ago