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Troyanec [42]
3 years ago
14

What is the value of the expression

Mathematics
2 answers:
Arturiano [62]3 years ago
5 0

Answer:

OA) 14

Step-by-step explanation:

2((7+1)-1)

2(8-1)

You could expand the brackets then simplify or just simplify now. It will be better to simplify now though but I will do both methods.

Simplifying first:

2(7) = 2 × 7 = 14

Our answer is 14 So answer is OA) 14

Expanding first then simplifying:

2(8-1) = 16-2 = 14

Our answer is 14 So answer is OA) 14

baherus [9]3 years ago
4 0

Answer:

14

Step-by-step explanation:

Substitute the values into the equation.

2((a +b) - b)

2((7 + 1) -1)

You can use Distribute first or Solve the parenthesis first it will still give the same answer.

Distributive method.

2((7 + 2) -2)

=((14 + 2) -2)

= 16 -2

=14

Or solve the parenthesis first.

2((7 + 1) -1)

=2(8 -1)

=2(7)

=14

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Answer:

Step-by-step explanation:

The quadratic formula for a equation of form

ax²+bx + c = 0 is

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For the first equation,

x²+3x-4=0,

we can match that up with the form

ax²+bx + c = 0

to get that

ax² =  x²

divide both sides by x²

a=1

3x = bx

divide both sides by x

3 = b

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. We can match this up because no constant multiplied by x could equal x² and no constant multiplied by another constant could equal x, so corresponding terms must match up.

Plugging our values into the equation, we get

x= \frac{-3 +- \sqrt{3^2-4(1)(-4)} }{2(1)} \\= \frac{-3+-\sqrt{25} }{2} \\ = \frac{-3+-5}{2} \\= -8/2 or 2/2\\=  -4 or 1

as our possible solutions

Plugging our values back into the equation, x²+3x-4=0, we see that both f(-4) and f(1) are equal to 0. Therefore, this has 2 real solutions.

Next, we have

x²+3x+4=0

Matching coefficients up, we can see that a = 1, b=3, and c=4. The quadratic equation is thus

x= \frac{-3 +- \sqrt{3^2-4(1)(4)} }{2(1)}\\= \frac{-3 +- \sqrt{9-16} }{2}\\= \frac{-3 +- \sqrt{-7} }{2}\\

Because √-7 is not a real number, this has no real solutions. However,

(-3 + √-7)/2 and (-3 - √-7)/2 are both possible complex solutions, so this has two complex solutions

Finally, for

4x² + 1= 4x,

we can start by subtracting 4x from both sides to maintain the desired form, resulting in

4x²-4x+1=0

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x=\frac{-(-4) +- \sqrt{(-4)^2-4(4)(1)} }{2(4)} \\= \frac{4+-\sqrt{16-16} }{8} \\= \frac{4+-0}{8} \\= 1/2

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3 years ago
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3241004551 [841]
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6 0
3 years ago
Read 2 more answers
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Answer:

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Step-by-step explanation:

Let V_s\ and\ V_b be the volumes of the smaller and bigger cylinder.

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3 years ago
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Answer:

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Step-by-step explanation:

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