Answer:
13 ft/s
Step-by-step explanation:
t seconds after the boy passes under the balloon the distance between them is ...
d = √((15t)² +(45+5t)²) = √(250t² +450t +2025)
The rate of change of d with respect to t is ...
dd/dt = (500t +450)/(2√(250t² +450t +2025)) = (50t +45)/√(10t² +18t +81)
At t=3, this derivative evaluates to ...
dd/dt = (50·3 +45)/√(90+54+81) = 195/15 = 13
The distance between the boy and the balloon is increasing at the rate of 13 ft per second.
_____
The boy is moving horizontally at 15 ft/s, so his position relative to the spot under the balloon is 15t feet after t seconds.
The balloon starts at 45 feet above the boy and is moving upward at 5 ft/s, so its vertical distance from the spot under the balloon is 45+5t feet after t seconds.
The straight-line distance between the boy and the balloon is found as the hypotenuse of a right triangle with legs 15t and (45+5t). Using the Pythagorean theorem, that distance is ...
d = √((15t)² + (45+5t)²)
Answer: 50.4537849152
Hope this helped!
<span>
<u><em>Answer:</em></u>either y = 4.5
or y = -4.5
<u><em>Explanation:</em></u>To get the solution, we will need to isolate the y on one side of the equation.
<u>This can be done as follows:</u>
4y</span>²<span> = 81
</span>

<span>
y</span>²<span> = 20.25
y = +/- </span>√(20.25)<span>
either y = +</span>√<span>(20.25) = 4.5
or y = -</span>√<span>(20.25) = -4.5
Since there are no restrictions on the value of y, therefore, both answers would be accepted
Hope this helps :)</span>
From my notes I’ve the derivative of arctan(x)= 1/(1+x^2)
Answer:
x intercept=2
y intercept=6
Step-by-step explanation:
to find x and y intercepts, plug in 0 for x and y
x intercept-
6x+2(0)=12
6x=12
x=2
y intercept-
6(0)+2y=12
2y=12
y=6