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Levart [38]
2 years ago
10

Find X: tangent, cosine or sine?

Mathematics
1 answer:
Gnom [1K]2 years ago
4 0

Answer:

x ≈ 2.76

Step-by-step explanation:

Using the tangent ratio in the right triangle

tan78° = \frac{opposite}{adjacent} = \frac{AB}{BC} = \frac{13}{x} ( multiply both sides by x )

x × tan78° = 13 ( divide both sides by tan78° )

x = \frac{13}{tan78} ≈ 2.76 ( to 2 dec. places )

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7nadin3 [17]

Answer:

see explanation

Step-by-step explanation:

Under a rotation about the origin of 90°

a point (x, y ) → (- y, x ), thus

C(6, 6 ) → C'(- 6, 6 )

D(6, 8 ) → D'(- 8, 6 )

E(8, 10 ) → E'(- 10, 8 )

F(10, 8 ) → F'(- 8, 10 )

8 0
4 years ago
Multiple and divide signed numbers​
Bas_tet [7]

Answer:

Step-by-step explanation:

Multiply answer = - 106

Divide answer = 1.25

8 0
4 years ago
A new computer can complete a complex biochemistry calculation in 7 hours less than an older-model computer. Working together, t
Alchen [17]
The rate a computer works is 1/time. Working together, you add the rates.
Let new computer be x, old computer be y.
x = y - 7

\frac{1}{x} + \frac{1}{y} = \frac{1}{13} \\  \\ \frac{1}{y-7}+\frac{1}{y} = \frac{1}{13} \\  \\ \frac{2y-7}{y(y-7)} = \frac{1}{13} \\  \\ y(y-7) = 13(2y-7) \\  \\ y^2-33y+91 = 0 \\  \\ y = 29.96 \\  \\ x = y-7 = 29.96-7 = 22.96
Rounded to nearest tenth gives:
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6 0
3 years ago
Course Home
NNADVOKAT [17]

Answer:

(a) The amount of pure acid in 60 oz of 20% acid solution is 12 oz.

(b) The amount of pure acid in 60 oz of 25% acid solution is 15 oz.

(c) The amount of pure acid in 60 oz of 30% acid solution is 18 oz.

(d) The amount of pure acid in 60 oz of 50% acid solution is 30 oz.

Step-by-step explanation:

* <em>Lets explain how to solve the problem</em>

- The solution is a mixture of two or more substances

- A container of liquid contains 60 oz of solution

- The solution contains pure acid by different concentrations

- (a) 20% (b) 25% (c) 30% (d) 50%

- We want to find the number of ounces of the pure acid in each

 concentration

- Assume that the solution is 100%

- That means 100% represents 60 oz of solution

a)

- The percentage of pure acid is 20%

∵    solution     ⇒     pure acid

        100%               20%

        60                    The number of ounces

- By using cross multiplication

∴ The number of ounces = \frac{60*20}{100}= 12

(a) The amount of pure acid in 60 oz of 20% acid solution is 12 oz.

b)

- The percentage of pure acid is 25%

∵    solution    ⇒      pure acid

        100%               25%

        60                    The number of ounces

- By using cross multiplication

∴ The number of ounces = \frac{60*25}{100}= 15

(b) The amount of pure acid in 60 oz of 25% acid solution is 15oz.

c)

- The percentage of pure acid is 30%

∵    solution     ⇒     pure acid

        100%               30%

        60                    The number of ounces

- By using cross multiplication

∴ The number of ounces = \frac{60*30}{100}= 18

(c) The amount of pure acid in 60 oz of 30% acid solution is 18 oz.

d)

- The percentage of pure acid is 30%

∵    solution     ⇒     pure acid

        100%               50%

        60                    The number of ounces

- By using cross multiplication

∴ The number of ounces = \frac{60*50}{100}= 30

(d) The amount of pure acid in 60 oz of 50% acid solution is 30 oz.

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So baiscktlg I need these points cheers
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