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3 years ago

Demand for electrical services in your area is $12 million per year. It is expected to grow 10% compounded annually

2 answers:

8 0

$\qquad \textit{Amount for Exponential Growth} \\\\ A=P(1 + r)^t\qquad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{initial amount}\dotfill &\stackrel{millions}{\$12E6}\\ r=rate\to 10\%\to \frac{10}{100}\dotfill &0.10\\ t=\textit{elapsed time}\dotfill &5\\ \end{cases} \\\\\\ A=12E6(1 + 0.10)^{5}\implies A=12E6(1.1)^5\implies A=19326120$

astraxan [27]3 years ago

3 0

Answer:

$19.3 million

Step-by-step explanation:

The demand in 5 years can be found by using the given formula for exponential growth with the given beginning value, growth rate, and time.

E = B(1 +r)^t

You are given B = 12, r = 0.10, t = 5, so the ending value is ...

E = 12(1 +0.10)^5 = 12(1.61051) = 19.32612

Demand for electrical services in 5 years will be about $19.3 million per year.

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3 years ago

What is the midpoint of the line segment with endpoints (–1, 7) and (3, –3)?

Kipish [7]

The coordinates consist of x coordinate and y coordinate
(x₁,y₁) = (-1,7)
(x₂,y₂) = (3,-3)

To find the midpoint of x coordinate, use this following formula
x midpoint = (x₁ + x₂)/2
x midpoint = (-1 + 3) / 2
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ANSWER
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3 years ago

Describe the nature of the roots for this equation.<br> 3x^2+x-5= 0

m_a_m_a [10]

Answer:

<h2>This equation has no natural roots.</h2>

Step-by-step explanation:

$3x^2+x-5=0\\\\\text{Use the quadratic formula for}\ ax^2+bx+c=0\\\\x=\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}\\\\\text{For the given equation:}\\\\a=3,\ b=1,\ c=-5\\\\b^2-4ac=1^2-4(3)(-5)=1+60=61\\\\x=\dfrac{-1\pm\sqrt{61}}{(2)(3)}=\dfrac{-1\pm\sqrt{61}}{6}\notin\mathbb{N}$

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3 years ago

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Points B and B' have symmetry with respect to P. Find the coordinates of P when B is (2, 8) and B' is (2, 2). A. (2, 5) B. (0, 5

Alecsey [184]

Answer:

A. (2, 5)

Step-by-step explanation:

If B and B' have symmetry, then P is a midpoint between those points. We can determinate the location of point P by using the midpoint equation, whose vectorial form is:

$P(x,y) = \frac{1}{2}\cdot B(x,y)+\frac{1}{2}\cdot B'(x,y)$ (Eq. 1)

If we know that $B(x,y) = (2,8)$ and $B'(x,y) = (2,2)$ , then the location of P is:

$P(x,y) = \frac{1}{2}\cdot (2,8)+\frac{1}{2}\cdot (2,2)$

$P(x,y) = (1, 4)+(1,1)$

$P(x,y) = (2, 5)$

Which corresponds to option A.

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3 years ago