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2 years ago

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Demand for electrical services in your area is $12 million per year. It is expected to grow 10% compounded annually

2 answers:

sergey [27]2 years ago

8 0

$\qquad \textit{Amount for Exponential Growth} \\\\ A=P(1 + r)^t\qquad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{initial amount}\dotfill &\stackrel{millions}{\$12E6}\\ r=rate\to 10\%\to \frac{10}{100}\dotfill &0.10\\ t=\textit{elapsed time}\dotfill &5\\ \end{cases} \\\\\\ A=12E6(1 + 0.10)^{5}\implies A=12E6(1.1)^5\implies A=19326120$

astraxan [27]2 years ago

3 0

Answer:

$19.3 million

Step-by-step explanation:

The demand in 5 years can be found by using the given formula for exponential growth with the given beginning value, growth rate, and time.

E = B(1 +r)^t

You are given B = 12, r = 0.10, t = 5, so the ending value is ...

E = 12(1 +0.10)^5 = 12(1.61051) = 19.32612

Demand for electrical services in 5 years will be about $19.3 million per year.

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Two boats started to move towards each other from two docks, located 30 miles apart. One boat moved at a speed of 3 miles per ho

blagie [28]

Answer:

3.333 hours

Step-by-step explanation:

Given the total distance is 30 miles, and boat 1 travels at 3 mph and boat 2 travels at 6 mph, and the time for both is the same. Distance is speed S times time T so

30 = D(boat 1) + D(boat 2)

30 = (S1 * T) + (S2 * T)

30 = 3T + 6T

30 = 9T

3.333 = T

5 0

2 years ago

What is 6/3 as a mixed number?

Reptile [31]

The mixed number of 6/3 is 2

Explanation

Nothing it’s just what it is

3 0

2 years ago

The chair of the operations management department at Quality University wants to construct a p-chart for determining whether the

sasho [114]

Answer:

Prof B and Prof D

Step-by-step explanation:

Step-by-step explanation:

From the question we are told that

Sample size 100

Instructor Number of Failures

Prof. A 13

Prof. B 0

Prof. C 11

Prof. D 16

Confidence level= 0.95

From Z table

Z=1.96

Generally proportion for failure is mathematically given as

$Proportion\ of\ Failure\ P=\frac{Number\ of\ Failure\ N}{Sample\ size\ S}$

$P=\frac{N}{S}$

For Prof A

$P_A=\frac{N_A}{S}$

$P_A=\frac{13}{100}$

$P_A=0.13$

For Prof B

$P_B=\frac{N_B}{S}$

$P_B=\frac{0}{100}$

$P_B=0$

For Prof C

$P_C=\frac{N_C}{S}$

$P_C=\frac{11}{100}$

$P_C=0.11$

For Prof D

$P_D=\frac{N_D}{S}$

$P_D=\frac{16}{100}$

$P_D=0.16$

Generally the average proportional failure is mathematically given as

$P_a_v_g=\frac{0.13+0+0.11+0.16}{4}$

$P_a_v_g=0.10$

Therefore having this we calculate for the control limits

Generally the upper control limit UCl is mathematically given as

Upper control limits:

$UCL =P_a_v_g +Z\sqrt{\frac{P_a_v_g(1-P_a_v_g) }{S} }$

$UCL =0.1 +1.96\sqrt{\frac{0.1(1-0.1) }{100}}$

$UCL =0.1 +1.96*0.03$

$UCL =0.1 +0.0588$

$UCL =0.1588$

Generally the upper control limit UCl is mathematically given as

Lower limit control limits:

$UCL =P_a_v_g _Z\sqrt{\frac{P_a_v_g(1-P_a_v_g) }{S} }$

$UCL =0.1 -1.96\sqrt{\frac{0.1(1-0.1) }{100}}$

$UCL =0.1 -1.96*0.03$

$UCL =0.1 -0.0588$

$UCL =0.0412$

Therefore the Range is 0.0412 to 0.1588

Given the range 0.0412 to 0.1588 Prof B and Prof D are outside the Range making them the correct options

4 0

2 years ago

What is the value of <img src="https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B1331%7D" id="TexFormula1" title="\sqrt[3]{1331}" alt="\s

Umnica [9.8K]

Answer:im not sure i wish i can help but goodluck

Step-by-step explanation:

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2 years ago

Evaluate the numerical expression below

Komok [63]

Use PEMDAS:

P Parentheses first

E Exponents (ie Powers and Square Roots, etc.)

MD Multiplication and Division (left-to-right)

AS Addition and Subtraction (left-to-right)

-----------------------------------------------------------------------

$4.3+45\cdot2^2-53=4.3+45\cdot4-53=4.3+180-53=184.3-53=131.3$

3 0

2 years ago