Answer:
B, 24 (second answer choice)
Step-by-step explanation:
4r+7s=23
r-2s=17
8r+14s=46
7r-14s=119
15r=165
r=11
11-2s=17..........by putting value of r in ii
-2s=17-11
2s= -6
s= -3
3r+3s=3*11+3(-3) you get this by putting values of r and s
=33-9
=24 (B)
To get the Y values use the equation Y = MX and substitute the X and M values So for the first one you would get Y = -3 x -1 leaving Y as 3 then for the second you do Y = -3 x 0 giving you Y = 0 the third would be Y = -3 x 1 so Y would be -3 and you give the last one a shot >.O best of luck!
Answer:
The second time when Luiza reaches a height of 1.2 m = 2 08 s
Step-by-step explanation:
Complete Question
Luiza is jumping on a trampoline. Ht models her distance above the ground (in m) t seconds after she starts jumping. Here, the angle is entered in radians.
H(t) = -0.6 cos (2pi/2.5)t + 1.5.
What is the second time when Luiza reaches a height of 1.2 m? Round your final answer to the nearest hundredth of a second.
Solution
Luiza is jumping on trampolines and her height above the levelled ground at any time, t, is given as
H(t) = -0.6cos(2π/2.5)t + 1.5
What is t when H = 1.2 m
1.2 = -0.6cos(2π/2.5)t + 1.5
0.6cos(2π/2.5)t = 1.2 - 1.5 = -0.3
Cos (2π/2.5)t = (0.3/0.6) = 0.5
Note that in radians,
Cos (π/3) = 0.5
This is the first time, the second time that cos θ = 0.5 is in the fourth quadrant,
Cos (5π/3) = 0.5
So,
Cos (2π/2.5)t = Cos (5π/3)
(2π/2.5)t = (5π/3)
(2/2.5) × t = (5/3)
t = (5/3) × (2.5/2) = 2.0833333 = 2.08 s to the neareast hundredth of a second.
Hope this Helps!!!
Answer:
The integers are (x, y) = (40, 8).
Step-by-step explanation:
x = 5y
xy = 320
Substitute the first equation into the second equation.
(5y)(y) = 320
5y^2 = 320
y^2 = 64
y = 8 (y must be positive)
The integers are (x, y) = (40, 8).
value of x is: x= i and x= -i
Step-by-step explanation:
We need to find the value of x from
using quadratic formula.
The term is: ![x^2+1=0](https://tex.z-dn.net/?f=x%5E2%2B1%3D0%E2%80%8B)
The quadratic formula is:
![x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}\\](https://tex.z-dn.net/?f=x%3D%5Cfrac%7B-b%5Cpm%5Csqrt%7Bb%5E2-4ac%7D%7D%7B2a%7D%5C%5C)
Where a = 1, b=0,c=1
Putting values:
![x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}\\x=\frac{0\pm\sqrt{(0)^2-4(1)(1)}}{2(1)}\\x=\frac{\pm\sqrt{-4}}{2}\\x=\frac{\pm2i}{2}\\x=\pm i](https://tex.z-dn.net/?f=x%3D%5Cfrac%7B-b%5Cpm%5Csqrt%7Bb%5E2-4ac%7D%7D%7B2a%7D%5C%5Cx%3D%5Cfrac%7B0%5Cpm%5Csqrt%7B%280%29%5E2-4%281%29%281%29%7D%7D%7B2%281%29%7D%5C%5Cx%3D%5Cfrac%7B%5Cpm%5Csqrt%7B-4%7D%7D%7B2%7D%5C%5Cx%3D%5Cfrac%7B%5Cpm2i%7D%7B2%7D%5C%5Cx%3D%5Cpm%20i)
So, value of x is: x= i and x= -i
Keywords: Quadratic formula
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