1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Bas_tet [7]
3 years ago
9

How can bargain-shopping help spending?

Mathematics
1 answer:
Over [174]3 years ago
5 0

Answer: It is shopping around for the best prices and saves money.

Step-by-step explanation: Bargain has the word "gain" in it. That's the best way I would look at it. Therefor I would cross out any other option that has to do with no benefit or the loss of something. Because we you bargain, you're getting multiple of something for a good price or maybe getting something that's on sale for a good price. For example: Buy 1 get 1 free items.

You might be interested in
What is £300 divided into a ratio of 3:7
3241004551 [841]
A) sum 3 + 7 =10
b) divide <span> £</span>300 ÷ 10 = <span> £</span>30
c) multiply:
     3 x 30 = <span> £</span>90
     7 x 30 = <span> £</span>210

Values are:  £90 and <span> £210</span>



5 0
3 years ago
Read 2 more answers
ACFG is a parallelogram, If AX = 4y + 3 and XF = 2y + 7, find AX.
pashok25 [27]

Answer:

AX=XF

4y+3=2y+7

4y-2y=7-3

2y=4

y=2

then,

AX=4y+3

=4×2+3

=8+3

=11

3 0
3 years ago
<img src="https://tex.z-dn.net/?f=%5Clim_%7Bx%5Cto%20%5C%200%7D%20%5Cfrac%7B%5Csqrt%7Bcos2x%7D-%5Csqrt%5B3%5D%7Bcos3x%7D%20%7D%7
salantis [7]

Answer:

\displaystyle  \lim_{x \to 0} \frac{\sqrt{cos(2x)} - \sqrt[3]{cos(3x)}}{sin(x^2)} = \frac{1}{2}

General Formulas and Concepts:

<u>Calculus</u>

Limits

Limit Rule [Variable Direct Substitution]:                                                                     \displaystyle \lim_{x \to c} x = c

L'Hopital's Rule

Differentiation

  • Derivatives
  • Derivative Notation

Basic Power Rule:

  1. f(x) = cxⁿ
  2. f’(x) = c·nxⁿ⁻¹

Derivative Rule [Chain Rule]:                                                                                    \displaystyle \frac{d}{dx}[f(g(x))] =f'(g(x)) \cdot g'(x)

Step-by-step explanation:

We are given the limit:

\displaystyle  \lim_{x \to 0} \frac{\sqrt{cos(2x)} - \sqrt[3]{cos(3x)}}{sin(x^2)}

When we directly plug in <em>x</em> = 0, we see that we would have an indeterminate form:

\displaystyle  \lim_{x \to 0} \frac{\sqrt{cos(2x)} - \sqrt[3]{cos(3x)}}{sin(x^2)} = \frac{0}{0}

This tells us we need to use L'Hoptial's Rule. Let's differentiate the limit:

\displaystyle  \lim_{x \to 0} \frac{\sqrt{cos(2x)} - \sqrt[3]{cos(3x)}}{sin(x^2)} = \displaystyle  \lim_{x \to 0} \frac{\frac{-sin(2x)}{\sqrt{cos(2x)}} + \frac{sin(3x)}{[cos(3x)]^{\frac{2}{3}}}}{2xcos(x^2)}

Plugging in <em>x</em> = 0 again, we would get:

\displaystyle \lim_{x \to 0} \frac{\frac{-sin(2x)}{\sqrt{cos(2x)}} + \frac{sin(3x)}{[cos(3x)]^{\frac{2}{3}}}}{2xcos(x^2)} = \frac{0}{0}

Since we reached another indeterminate form, let's apply L'Hoptial's Rule again:

\displaystyle \lim_{x \to 0} \frac{\frac{-sin(2x)}{\sqrt{cos(2x)}} + \frac{sin(3x)}{[cos(3x)]^{\frac{2}{3}}}}{2xcos(x^2)} = \lim_{x \to 0} \frac{\frac{-[cos^2(2x) + 1]}{[cos(2x)]^{\frac{2}{3}}} + \frac{cos^2(3x) + 2}{[cos(3x)]^{\frac{5}{3}}}}{2cos(x^2) - 4x^2sin(x^2)}

Substitute in <em>x</em> = 0 once more:

\displaystyle \lim_{x \to 0} \frac{\frac{-[cos^2(2x) + 1]}{[cos(2x)]^{\frac{2}{3}}} + \frac{cos^2(3x) + 2}{[cos(3x)]^{\frac{5}{3}}}}{2cos(x^2) - 4x^2sin(x^2)} = \frac{1}{2}

And we have our final answer.

Topic: AP Calculus AB/BC (Calculus I/I + II)

Unit: Limits

6 0
3 years ago
How do I convert 4/5 to a percent
Gelneren [198K]
(4/5) x 100%
= 80%
=0.8
5 0
3 years ago
Suppose you received a job offer with a starting salary of $48,500 per year and a guaranteed raise of $1200 per year. Find the n
LuckyWell [14K]

Answer:

  • 7 years

Step-by-step explanation:

<u>This is going to be an arithmetic progression:</u>

  • 48500, 48500 + 1200, 48500 + 1200*2, ...

<u>So the first term is </u>

  • a₁ = 48500

<u>and the common difference is </u>

  • d = 1200

<u>Sum of AP is:</u>

  • S = (a₁ + aₙ)*n/2 = (2a₁ + (n - 1)d)*n/2

<u>Substitute and solve for n:</u>

  • (2*48500 + (n - 1)*1200)*n/2 = 321000
  • (97000 + 1200n - 1200)n = 642000
  • 1200n² + 95800n - 642000 = 0
  • 6n² + 479n - 3210 = 0

<u>Solving we get a positive root of:</u>

  • n ≈ 6.21 and it rounds up to 7 years

3 0
3 years ago
Other questions:
  • Answer in mixed numbers if possible
    10·2 answers
  • Alex wants to have $3000 in his bank account after 4 years. If the account earns 6% interest compounded 2 times per year, how mu
    6·2 answers
  • Heeeeeeeeeeeeeeeeeelpppppppppppp
    7·1 answer
  • I need help!! on 9 and 10 plzz help
    10·1 answer
  • If you know a point on a line and you know the equation of a line parallel to this line, explain how to write the line’s equatio
    6·1 answer
  • In the state legislature, there were 119 more members in the House of Representatives than in the senate. If there were m member
    12·1 answer
  • How much is 3/4 of 12
    14·2 answers
  • You make 12 equal payments. You pay a total of $2052. How much is each payment?
    13·2 answers
  • What is the product please <br> -1/6 x 7 x 2/5
    7·2 answers
  • HELP PLEEES ASAP i am so lost<br> show your work
    6·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!