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tester [92]
3 years ago
12

Express the fractions 3/4, 7/16, and 5/8 with the LCD. A. 9/16, 49/16, 36/16 B. 12/16, 7/16, 10/16 C. 24/32, 14/32, 24/32 D. 3/4

, 2/4, 3/4
Mathematics
1 answer:
True [87]3 years ago
6 0

Answer:

B.

Step-by-step explanation:

the denominator you want is 16 so 4(4) is 16, which makes 3(4) 12 so 12/16. 7/16 is already perfect. 8(2) is 16 therefore 5(2) is 10 which makes 10/16.

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1 3 6 10 15

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WILL MARK BRAINLIST On the coordinate plane below, plot and label each point.
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Red is the positive integers and blue is the negative integer.

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Use series to verify that<br><br> <img src="https://tex.z-dn.net/?f=y%3De%5E%7Bx%7D" id="TexFormula1" title="y=e^{x}" alt="y=e^{
SVETLANKA909090 [29]

y = e^x\\\\\displaystyle y = \sum_{k=1}^{\infty}\frac{x^k}{k!}\\\\\displaystyle y= 1+x+\frac{x^2}{2!} + \frac{x^3}{3!}+\ldots\\\\\displaystyle y' = \frac{d}{dx}\left( 1+x+\frac{x^2}{2!} + \frac{x^3}{3!}+\frac{x^4}{4!}+\ldots\right)\\\\

\displaystyle y' = \frac{d}{dx}\left(1\right)+\frac{d}{dx}\left(x\right)+\frac{d}{dx}\left(\frac{x^2}{2!}\right) + \frac{d}{dx}\left(\frac{x^3}{3!}\right) + \frac{d}{dx}\left(\frac{x^4}{4!}\right)+\ldots\\\\\displaystyle y' = 0+1+\frac{2x^1}{2*1} + \frac{3x^2}{3*2!} + \frac{4x^3}{4*3!}+\ldots\\\\\displaystyle y' = 1 + x + \frac{x^2}{2!}+ \frac{x^3}{3!}+\ldots\\\\\displaystyle y' = \sum_{k=1}^{\infty}\frac{x^k}{k!}\\\\\displaystyle y' = e^{x}\\\\

This shows that y' = y is true when y = e^x

-----------------------

  • Note 1: A more general solution is y = Ce^x for some constant C.
  • Note 2: It might be tempting to say the general solution is y = e^x+C, but that is not the case because y = e^x+C \to y' = e^x+0 = e^x and we can see that y' = y would only be true for C = 0, so that is why y = e^x+C does not work.
6 0
3 years ago
Using dimensional analysis, what unit of time will make the statement true?
frosja888 [35]

The unit of time that will make the statement true is "day"

<h3>What unit of time will make the statement true?</h3>

The conversion equation is given as:

Seconds + Seconds/? * day = seconds

Represent the blank with a variable (x)

So, we have:

Seconds + Seconds/x * day = seconds

Subtract "seconds" from both sides of the equation

So, we have:

Seconds/x * day = seconds

Divide both sides of the equation by "seconds"

So, we have:

1/x * day = 1

Multiply both sides by x

x= day

Hence, the unit of time that will make the statement true is "day"

Read more about time at:

brainly.com/question/17146782

#SPJ1

4 0
2 years ago
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