Answer:

Step-by-step explanation:

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Answer:
His wet feet froze the faster, and his exposed fingers numbed the faster, though they had not yet begun to freeze.
Step-by-step explanation:
Did this for edmentum and got it correct.
Its 21 + 3 x by A yourwelcom
Answer:
The 95% confidence interval estimate of the population proportion of managers who have caught salespeople cheating on an expense report is (0.5116, 0.6484).
Step-by-step explanation:
In a sample with a number n of people surveyed with a probability of a success of
, and a confidence level of
, we have the following confidence interval of proportions.

In which
z is the zscore that has a pvalue of
.
In the survey on 200 managers, 58% of the managers have caught salespeople cheating on an expense report.
This means that 
95% confidence level
So
, z is the value of Z that has a pvalue of
, so
.
The lower limit of this interval is:

The upper limit of this interval is:

The 95% confidence interval estimate of the population proportion of managers who have caught salespeople cheating on an expense report is (0.5116, 0.6484).