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1 year ago

Adding and subtracting I need it right now the answer

Mathematics

1 answer:

kumpel [21]1 year ago

3 0

Answer:

Just give me the questions and ill do it

Step-by-step explanation:

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In the Uffizi gallery in Florence, Italy, there is a room built by Buontalenti called the Tribune (La Tribuna in Italian). This

Leto [7]

Answer:

135 degrees

Step-by-step explanation:

135 degrees form the interior angle of a regular octagon

5 0

1 year ago

Read 2 more answers

I NEED HELP ASAP PLEASE!! I WILL AWARD BRAINLIEST

Irina-Kira [14]

9514 1404 393

Answer:

x ≥ 7
54 -6m
y -x

Step-by-step explanation:

You have to realize that the absolute value function will change the sign of its argument only if that argument is negative.

108. |x -7| = x -7 . . . . . true for x-7≥0

x ≥ 7 . . . . makes the statement true

1a. When m < 9, the value 6m is less than 54, so 6m-54 < 0. That means the absolute value function changes the sign of its argument:

54 -6m . . . . . simplified form for m < 9

1b. |y -x| = y -x . . . when y > x, the argument of the absolute value is positive

6 0

2 years ago

¿por qué no está definida la raíz de índice par de un número negativo?

amid [387]

Answer:

Porque se convierte en positivo cada vez que haces la raíz cuadrada.

3 0

2 years ago

Determine the value of y, if x is 6.<br> y = |x|-1<br> Answer:

Karolina [17]

Answer:

Step-by-step explanation:

8 0

2 years ago

(cot^2x - 1)/(csc^2x) = cos2x

Alex787 [66]

Answer:

Step-by-step explanation:

The idea here is to get the left side simplified down so it is the same as the right side. Consequently, there are 3 identities for cos(2x):

$cos(2x)=cos^2x-sin^2x$ ,

$cos(2x)=1-2sin^2x$ , and

$cos(2x)=2cos^2x-1$

We begin by rewriting the left side in terms of sin and cos, since all the identities deal with sines and cosines and no cotangents or cosecants. Rewriting gives you:

$\frac{\frac{cos^2x}{sin^2x} -\frac{sin^2x}{sin^2x} }{\frac{1}{sin^2x} }$

Notice I also wrote the 1 in terms of sin^2(x).

Now we will put the numerator of the bigger fraction over the common denominator:

$\frac{\frac{cos^2x-sin^2x}{sin^2x} }{\frac{1}{sin^2x} }$

The rule is bring up the lower fraction and flip it to multiply, so that will give us:

$\frac{cos^2x-sin^2x}{sin^2x} *\frac{sin^2x}{1}$

And canceling out the sin^2 x leaves us with just

$cos^2x-sin^2x$ which is one of our identities.

5 0

2 years ago