Answer:
400 lb of salt
Step-by-step explanation:
Let us assume the water flows into the rank for x minutes.
There is an initial of 1000 gallons of water in the tank and water flows in through one pipe at 4 gal/min and through another pipe at 6 gal/min. In x minute, the amount of water in the tank = 1000 + 4x + 6x = 1000 + 10x
Water flows out at 5 gal/min, therefore in x minute the amount of water in the tank = 1000 + 10x - 5x = 1000 + 5x
The tank begins to overflow when it is full (has reached 1500 gallons). Therefore:
1500 = 1000 + 5x
5x = 1500 - 1000
5x = 500
x = 100 minutes.
1/2 lb salt per gallon flows into the tank at 4 gal/min and 1/3 lb of salt is flowing in at 6 gal/min, in 100 min the amount of salt that entered the tank = 4 gal/min × 100 min × 1/2 lb/gal + 6 gal/min × 100 min × 1/3 lb/gal= 400 lb
Therefore the amount of salt is in the tank when it is about to overflow = 400 lb of salt
I have no clue but you could ask your teacher to help u with it no jk the answer is -7
A= 1/360 m•pi r^2
11/2= 1/360 m• pi (3)^2
11/2= 1/360 m• pi • 9
Divide 360 by 9
11/2= 1/40 m pi
Cross multiply
440=2pi m
Divide both sides by 2pi
m= 70.02817 degrees round if necessary
Draw a number line and mark -7 -3 on the line and write the formula ex: | < x < 7 so basically mark the graph from -3 to -7 and count them and whatever one it stops on when you count mark then draw a straight line and that’s your formula :).
Answer:
If 550 toys are made in a day, and 6% of them are defective, about 33 of them will be defective.
Step-by-step explanation:
To calculate the number of toys that will be defective, move the decimal of the percentage 2 place to the left. So the 6% will turn into 0.06, then you would multiply 550 by 0.06. Resulting in about 33 toys being defective.
6% = 0.06
-
550 x 0.06 = 33
