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Allushta [10]
2 years ago
8

Each cube in the prism is one cubic unit.

Mathematics
1 answer:
Ksivusya [100]2 years ago
3 0

Answer:

all you do is 5x3x6
LengthxWidthxHeight

5x3x9 is 90

Step-by-step explanation:

90 units³

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Factor completely 5ax2 − 20x3 + 2a − 8x.
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C

Step-by-step explanation:

5ax²-20x³+2a-8x

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2. Two puppies together weigh 22 kilograms 300 grams. If one
monitta

Answer:

B = 12800 grams or 12kg 800 grams.

Step-by-step explanation:

Let the two puppies be A and B respectively.

Translating the word problem into an algebraic expression, we have;

A + B = 22kg 300g

A = 9kg 500g

Conversion;

1 Kilograms = 1000 grams.

9kg 500g = 9*1000 + 500 = 9500 grams

22kg 300g = 22*1000 + 300 = 22300 g

Substituting into the above formula, we have;

9500 + B = 22300

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B = 12800 grams or 12kg 800 grams

6 0
3 years ago
Use the surface integral in​ Stokes' Theorem to calculate the circulation of the field Bold Upper F equals x squared Bold i plus
Alinara [238K]

Answer:

The circulation of the field f(x) over curve C is Zero

Step-by-step explanation:

The function f(x)=(x^{2},4x,z^{2}) and curve C is ellipse of equation

16x^{2} + 4y^{2} = 3

Theory: Stokes Theorem is given by:

I= \int \int\limits {{Curl f\cdot \hat{N }} \, dx

Where, Curl f(x) = \left[\begin{array}{ccc}\hat{i}&\hat{j}&\hat{k}\\\frac{∂}{∂x} &\frac{∂}{∂y} &\frac{∂}{∂z} \\F1&F2&F3\end{array}\right]

Also, f(x) = (F1,F2,F3)

\hat{N} = grad(g(x))

Using Stokes Theorem,

Surface is given by g(x) = 16x^{2} + 4y^{2} - 3

Therefore, tex]\hat{N} = grad(g(x))[/tex]

\hat{N} = grad(16x^{2} + 4y^{2} - 3)

\hat{N} = (32x,8y,0)

Now,  f(x)=(x^{2},4x,z^{2})

Curl f(x) = \left[\begin{array}{ccc}\hat{i}&\hat{j}&\hat{k}\\\frac{∂}{∂x} &\frac{∂}{∂y} &\frac{∂}{∂z} \\F1&F2&F3\end{array}\right]

Curl f(x) = \left[\begin{array}{ccc}\hat{i}&\hat{j}&\hat{k}\\\frac{∂}{∂x} &\frac{∂}{∂y} &\frac{∂}{∂z} \\x^{2}&4x&z^{2}\end{array}\right]

Curl f(x) = (0,0,4)

Putting all values in Stokes Theorem,

I= \int \int\limits {Curl f\cdot \hat{N} } \, dx

I= \int \int\limits {(0,0,4)\cdot(32x,8y,0)} \, dx

I= \int \int\limits {(0,0,4)\cdot(32x,8y,0)} \, dx

I=0

Thus, The circulation of the field f(x) over curve C is Zero

3 0
3 years ago
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