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Fed [463]
3 years ago
14

Is this correct? If not please help me out.

Mathematics
1 answer:
never [62]3 years ago
4 0
Yes I believe so !!!
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X + y = 3 2x + 2y = -4​
zaharov [31]

Answer:

(x,y)= (2/15, -(62/15)

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
PLEASE HELP! <br><br> i’ll mark brainliest if you’re correct!
Jobisdone [24]

Answer:

y = 5

Step-by-step explanation:

Since this is an isosceles triangle, Angle B and Angle C are equivalent. We can use this to find x

3x = 75

x = 25

Angles in a triangle add up to 180, so knowing the measure of Angle B and Angle C, we can find the measure of Angle A

Angle A = 180-(75+75)

Angle A = 180-150

Angle A = 30

We know Angle A = 4y+10

4y + 10 = 30

4y = 20

y = 5

6 0
2 years ago
Todd bought a game for $36 with a coupon for 25% off. How much would it have cost without the coupon?
kotykmax [81]

Answer:

Step-by-step explanation:

x*0.75=36

x=36/0.75=48 $

6 0
3 years ago
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The area of a square postcard is 25 square inches. How long is each side postcard?​
ivolga24 [154]

Answer:

5 inches

Step-by-step explanation:

To find the area of a square the formula is A = bh which with a square is essentially one side squared. We know this because every side of a square is the same. We also know that 5 squared is 25 meaning the answer is 5 inches(You could also use the formula A = bh : A = 5 x 5 : A = 25).

7 0
3 years ago
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Let f(x) = log(x). Find values of a such that f(kaa) = kf(a).
meriva

Answer:

a = k^{\frac{1}{k-2}}

Step-by-step explanation:

Given:

f(x) = log(x)

and,

f(kaa) = kf(a)

now applying the given function, we get

⇒ log(kaa) = k × log(a)

or

⇒ log(ka²) = k × log(a)

Now, we know the property of the log function that

log(AB) = log(A) + log(B)

and,

log(Aᵇ) = b × log(A)

Thus,

⇒ log(k) + log(a²) = k × log(a)         (using log(AB) = log(A) + log(B) )

or

⇒ log(k) + 2log(a) = k × log(a)            (using log(Aᵇ) = b × log(A) )

or

⇒ k × log(a) - 2log(a) = log(k)

or

⇒ log(a) × (k - 2) = log(k)

or

⇒ log(a) = (k - 2)⁻¹ × log(k)

or

⇒ log(a) = \log(k^{\frac{1}{k-2}})          (using log(Aᵇ) = b × log(A) )

taking anti-log both sides

⇒ a = k^{\frac{1}{k-2}}

3 0
3 years ago
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