Answer:

Step-by-step explanation:
<u>The full question:</u>
<em>"A committee has eleven members. there are 3 members that currently serve as the boards chairman, ranking members, and treasurer. each member is equally likely to serve in any of the positions. Three members are randomly selected and assigned to be the new chairman, ranking member, and treasurer. What is the probability of randomly selecting the three members who currently hold the positions of chairman, ranking member, and treasurer and reassigning them to their current positions?"</em>
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The permutation of choosing 3 members from a group of 11 would be:
P(n,r) = 
Where n would be the total [in this case n is 11] & r would be 3
Which is:
P(11,3) = 
So there are total of 990 possible way and there is ONLY ONE WAY for them to be reassigned. Hence the probability would be:
1/990
AB=DC because they have the same side lengths
Answer:
2.8 litres
Step-by-step explanation:
8.22 mg per 3.039 mL
2.704 mg per 1 mL
7.469 gram = 7469 milligrams
7469 milligrams per 2,761.34927mL
= 2.761 litres = 2.8 litres
Subtract these 2 equations,
5x-5x +3y-y = -4-6
2y = -10
y = -5
-5 is your answer.