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Fed [463]
3 years ago
14

Is this correct? If not please help me out.

Mathematics
1 answer:
never [62]3 years ago
4 0
Yes I believe so !!!
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How to do this question plz answer me ​
Sati [7]

Answer:

d =  \frac{4 - 3c}{c + 1}

Step-by-step explanation:

To make d the subject of formula, we need to rearrange the equation such that we arrive at d= _____.

c =  \frac{4 - d}{d + 3}

<em>Remove the fraction by multiplying (d +3) on both sides:</em>

c(d + 3) = 4 - d

<em>Expand</em><em>:</em>

<em>cd + 3c = 4 - d</em>

<em>Bring</em><em> </em><em>all</em><em> </em><em>the</em><em> </em><em>d</em><em> </em><em>terms</em><em> </em><em>to</em><em> </em><em>one</em><em> </em><em>side</em><em> </em><em>and</em><em> </em><em>move</em><em> </em><em>the</em><em> </em><em>others</em><em> </em><em>to</em><em> </em><em>the</em><em> </em><em>other</em><em> </em><em>side</em><em> </em><em>of</em><em> </em><em>the</em><em> </em><em>equation</em><em>:</em>

cd + d = 4 - 3c

<em>Factorise</em><em> </em><em>d</em><em> </em><em>out</em><em>:</em>

<em>d(c + 1) = 4 - 3c</em>

<em>Divide</em><em> </em><em>by</em><em> </em><em>(</em><em>c</em><em> </em><em>+</em><em>1</em><em>)</em><em> </em><em>on</em><em> </em><em>both</em><em> </em><em>sides</em><em>:</em>

<em>d =  \frac{4 - 3c}{c + 1}</em>

7 0
3 years ago
What’s 599,600 in scientific notation
Vlada [557]

Answer:5.9 x10-5

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
Find the product.<br> (n^3)^2 * (n^5)^4
Brums [2.3K]
Hi

(n^3)^2 × (n^5)^4 = n^6 × n^20 = n^26

<span>Answer: n^26</span>
8 0
3 years ago
Can u plz help me I don’t really get it plz show your work
rosijanka [135]

Answer:

2.2r

Step-by-step explanation:

3.7-1.5=2.2

8 0
3 years ago
Plz help me without putting links or files
densk [106]

Answer:

Step-by-step explanation:

4(1/4) + 3/8 + 3(1/2) + 5/8 + 3/4

1 + 8/8 + 3/2 + 3/4

1 + 1 + 12/8 + 6/8

2 + 18/8

2 + 2 1/4

= 4 1/4 pounds

8 0
3 years ago
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